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Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

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displacement in the horizontal direction is denoted

by u together with a subscript identifying the joint

(e.g., u A ). A positive displacement u means that the

joint moves to the right.

SOLUTION

Equilibrium

Draw an FBD that exposes the internal axial force

in member (1). Assume tension in member (1).

The equilibrium equation for this FBD is

∑ Fx = F1

− 4kN = 0

∴ F = 4kN = 4 kN ( T)

1

Draw an FBD for member (2) and assume tension

in member (2).

The equilibrium equation for this FBD is

∑ Fx = F2

+ 2(10 kN) − 4 kN = 0

∴ F2 = − 16 kN = 16 kN ( C)

Similarly, draw an FBD for member (3) and assume

tension in the member. Although two different

FBDs are possible, the simpler one is shown.

The equilibrium equation for this FBD is

∑ Fx =− F3

+ 8kN = 0

∴ F = 8kN = 8 kN ( T)

3

Before proceeding, plot the internal forces F 1 , F 2 ,

and F 3 acting in the compound member. It is the

internal forces that create deformations in the axial

members, not the external forces applied at

joints A, B, C, and D.

y

10 kN

12 kN

4 kN F 1

8 kN

(1)

(2)

(3)

x

A 10 kN B C 12 kN D

2.0 m 2.5 m 3.0 m

y

10 kN

12 kN

4 kN

F 2

8 kN

(1)

(2)

(3)

x

A 10 kN B C 12 kN D

2.0 m 2.5 m 3.0 m

y

10 kN

12 kN

4 kN

F 3

8 kN

(1)

(2)

(3)

x

A 10 kN B C 12 kN D

2.0 m 2.5 m 3.0 m

y

10 kN

12 kN

4 kN

(1) (2) (3)

8 kN

A 10 kN B C 12 kN D

Tension

4 kN

8 kN

Compression

–16 kN

Axial force diagram for compound member.

x

Problem-Solving Tip: When drawing an FBD that cuts through an axial member,

assume that the internal force is tension and draw the force arrow so that it is directed

away from the cut surface. If the computed internal force value turns out to be a

positive number, then the assumption of tension is confirmed. If the computed value

turns out to be a negative number, then the internal force is actually compression.

Force–Deformation Relationships

The relationship between the deformation of an axial member and its internal force is

expressed by Equation (5.2):

δ =

Since the internal force is assumed to be a tensile force, the axial deformation is assumed

to be an elongation. If the internal force is compressive, then the use of a negative value

for the internal force F in the preceding equation will produce a negative deformation—in

other words, a contraction.

FL

AE

89

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