Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

Answers to Odd Numbered
Problems
Chapter 1
P1.1 σ = 122.2 MPa
P1.3 t min = 16.09 mm
P1.5 b 2 = 27.1 mm
P1.7 d 1 = 1.382 in., d 2 = 0.853 in.,
d 3 = 1.596 in.
P1.9 σ 1 = 93.2 MPa (T)
P1.11 w = 13.01 kN/m
P1.13 P max = 55.2 kips
P1.15 (a) σ = 4,380 psi (T)
(b) σ = 1,730 psi (T)
P1.17 τ avg = 101.9 psi
P1.19 τ avg = 17,740 psi
P1.21 d min = 0.824 in.
P1.23 a ≥ 324 mm
P1.25 5 in. × 5 in. plate at A, 6 in. ×
6 in. plate at B
P1.27 σ b = 20.6 MPa
P1.29 (a) τ avg = 18,050 psi
(b) σ b = 28,400 psi
832
P1.31 (a) τ B = 11.58 MPa
(b) σ b = 18.19 MPa
P1.33 (a) d min = 14.42 mm
(b) d min = 16.33 mm
(c) d min = 6.60 mm
P1.35 d min = 19.54 mm
P1.37 σ n = 37.6 psi, τ nt = 53.7 psi
P1.39 P max = 152.3 kips
P1.41 τ nt = 11.75 MPa
Chapter 2
P2.1 e 1 = 825 me
P2.3 e AB = 8,300 me
P2.5 e 1 = −1,103 me
P2.7 (a) e 1 = 900 me
(b) e 1 = 1,127 me
(c) e 1 = 275 me
2
γ L
P2.9 (a) δ =
6E
γ L
(b) e avg =
6E
γ L
(c) e max =
3E
P2.11 γ P′ = −9,170 mrad
P2.13 γ Q = −3,750 mrad
P2.15 (a) e QS = −4,410 me
(b) γ P′ = 5,430 mrad
P2.17 (a) Dw = 1.896 mm
(b) Dd = 1.138 mm
P2.19 96.1°F
P2.21 u D = 0.522 mm ←
Chapter 3
P3.1 (a) σ PL = 43.0 ksi
(b) E = 15,860 ksi
(c) ν = 0.343
P3.3 (a) E = 2.92 GPa
(b) ν = 0.410
(c) Db = 0.1900 mm
P3.5 E = 3.19 GPa
P3.7 P = 35.3 kips (c)
P3.9 (a) permanent set =
0.0035 mm/mm
(b) bar length unloaded =
351.225 mm
(c) σ PL = 444 MPa