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Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

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208

EQuILIbRIuM OF bEAMS

w(x)

w A

w B

w C

w D

w E

w F

w G

A B C D E F G

x

The change in shear force, ∆V, between

any two locations is equal to the area

under the distributed-load curve.

V E

V F

∆V

V

M

The positive direction for a

concentrated load is upward.

M B

∆M

An upward load P causes the

shear diagram to jump upward.

Similarly, a downward load P

causes the shear diagram to

jump downward.

M

V

∆x

P 0

O

FIGURE 7.11a Free-body

diagram of beam element

subjected to concentrated

load P 0 .

V O

M

M 0

∆x

M +∆M

V+∆V

M +∆M

V+∆V

FIGURE 7.11b Free-body

diagram of beam element

subjected to concentrated

moment M 0 .

The change in bending moment, ∆M, between any

two locations is equal to the area under the V curve.

FIGURE 7.10 Relationships between areas for the load, shear, and moment diagrams.

Regions of concentrated Loads and moments

Equations (7.1) through (7.4) were derived for a portion of the beam subjected to a distributed

load only. Next, consider the free-body diagram of a very thin portion of the beam (see

Figure 7.8a) directly beneath one of the concentrated loads (Figure 7.11a). Force equilibrium

for this free body can be stated as

Σ F = V + P − ( V +D V) = 0 ∴ D V = P

y 0 0

(7.5)

This equation shows that the change in shear force, DV, between the left and right sides of

a thin beam element is equal to the intensity of the external concentrated load P 0 acting on

the beam element. At the location of a positive external load, the shear-force diagram is

discontinuous: It “jumps” upward by an amount equal to the intensity of an upward concentrated

load. A downward external concentrated load causes the shear-force diagram to

jump downward. (See Example 7.1.)

Next, consider a thin beam element located at a concentrated moment (Figure 7.11b).

Moment equilibrium for this element can be expressed as

As Dx approaches zero,

M C

Σ M = −M −VD x + M + ( M + D M) = 0

O 0

D M = − M 0

(7.6)

The moment diagram is discontinuous at locations where external concentrated moments

are applied. Equation (7.6) reveals that the change in internal bending moment, DM, between

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