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Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

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332

SHEAR STRESS IN bEAMS

The shear stress τ as a function of the vertical coordinate y can now be determined from the

shear formula:

τ =

2

2

VQ V 1 ⎛ h

2

⎞ 6V

⎛ h

2

= × -

⎛ ⎞ ⎝

⎜ y

⎟ b = -

It

bh ⎝

⎜ y

⎟ (9.5)

3

z 1

3

2 4

4

bh b

⎝ 12 ⎠

The accuracy of Equation (9.6)

depends on the depth-to-width

ratio of the cross section. For

beams in which the depth is

much greater than the width,

Equation (9.6) can be considered

exact. As the cross section

approaches a square shape, the

true maximum horizontal shear

stress is somewhat greater than

that given by Equation (9.6).

Equation (9.5) is a second-order equation, which indicates that τ is distributed parabolically

with respect to y (Figure 9.10c). At y = ± h/2, τ = 0. The shear stress vanishes at the

extreme fibers of the cross section, since A′ = 0; consequently, Q = 0 at these locations.

There is no shear stress on a free surface of the beam. The maximum horizontal shear stress

occurs at y = 0, which is the neutral-axis location. At the neutral axis, the maximum horizontal

shear stress in a rectangular cross section is given by

VQ V 1

τ = = × ⎛

⎛ ⎞ ⎝ ⎜ h⎞

bh 3V

max

⎟ = =

It z 1

3

2 2 2 2bh

bh b

⎝ 12 ⎠

3

2

V

A

(9.6)

It is important to emphasize that Equation (9.6) gives the maximum horizontal shear stress

only for rectangular cross sections. Note that the maximum horizontal shear stress at the

neutral axis is 50 percent greater than the overall average shear stress given by τ = V/A.

To summarize, the shear stress intensity associated with an internal shear force V in

a rectangular cross section is distributed parabolically in the direction perpendicular to the

neutral axis (i.e., in the y direction) and uniformly in the direction parallel to the neutral

axis (i.e., in the z direction) (Figure 9.10d). The shear stress vanishes at the upper and

lower edges of the rectangular cross section and peaks at the neutral-axis location. It is

important to remember that shear stress acts on both transverse and longitudinal planes

(Figure 9.10e).

The expression “maximum shear stress” in the context of beam shear stresses is problematic.

In Chapter 12, the discussion of stress transformations will show that the state of

stress existing at any point can be expressed by many different combinations of normal and

shear stress, depending on the orientation of the plane surface upon which the stresses act.

(This notion was introduced previously in Section 1.5, pertaining to axial members, and

in Section 6.4, regarding torsion members.) Consequently, the expression “maximum

shear stress,” when applied to beams, could be interpreted to mean either

(a) the maximum value of τ = VQ/It for any coordinate y in the cross section, or

(b) the maximum shear stress at a particular point in the cross section when all possible

plane surfaces that pass through the point are considered.

In this chapter, to preclude ambiguity, the expression “maximum horizontal shear

stress” will be used in a context in which the maximum value of τ = VQ/It for any coordinate

y in the cross section is to be determined. Since shear stresses on perpendicular

planes must be equal in magnitude, it would be equally proper to use the expression

“maximum transverse shear stress” for this purpose. In Chapter 12, the notion of stress

transformations will be used to determine the maximum shear stress at a particular

point. In Chapter 15, maximum normal and shear stresses at specific points in beams

will be discussed in more detail.

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