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Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

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6.4 Stresses on oblique planes

The elastic torsion formula [Equation (6.6)] can be used to calculate the maximum shear

stress produced on a transverse section in a circular shaft by a torque. It is necessary to establish

whether the transverse section is a plane of maximum shear stress and whether there

are other significant stresses induced by torsion. For this study, the stresses at point A in the

shaft of Figure 6.8a will be analyzed. Figure 6.8b shows a differential element taken from

the shaft at A, as well as the shear stresses acting on transverse and longitudinal planes. The

stress τ xy may be determined by means of the elastic torsion formula and the equation τ yx = τ xy

(see Section 1.6). If the equations of equilibrium are applied to the free-body diagram of

Figure 6.8c, the following result is obtained:

We then have

Σ F = τ dA − τ ( dAcos θ)cos θ + τ ( dAsin θ)sinθ

= 0

t nt xy yx

2 2

τ = τ (cos θ − sin θ) = τ cos2θ

nt xy xy

(6.9)

and

from which it follows that

Σ F = σ dA − τ ( dAcos θ)sin θ − τ ( dAsin θ)cosθ

= 0

n n xy yx

σn = 2τxysinθcosθ = τxy

sin 2θ

(6.10)

These results are shown in the graph of Figure 6.9, from which it is apparent that the

maximum shear stress occurs on transverse and longitudinal diametral planes (i.e., longitudinal

planes that include the centerline of the shaft). The graph also shows that the

maximum normal stresses occur on planes oriented at 45° with the axis of the shaft and

perpendicular to the surface of the shaft. On one of these planes (θ = 45° in Figure 6.8b),

the normal stress is tensile, and on the other (θ = 135°), the normal stress is compressive.

Furthermore, the maximum magnitudes for both σ and τ are equal. Therefore, the

maximum shear stress given by the elastic torsion formula is also numerically equal

to the maximum normal stress that occurs at a point in a circular shaft subjected to

pure torsion.

T

A

y

FIGURE 6.8a Shaft subjected to

pure torsion.

140

x

T

τ xy

y

θ

τ yx

τ yx

τ xy

FIGURE 6.8b Differential

element at point A on the shaft.

x

t

y

τ

θ

n

x

xy dA cos

θ

dA cos

σn dA

θ

τnt dA

τyx dA sin θ

FIGURE 6.8c Free-body diagram of a wedgeshaped

portion of the differential element.

dA

dA sin θ

θθ

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