01.11.2021 Views

Timothy A. Philpot - Mechanics of materials _ an integrated learning system-John Wiley (2017)

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Since θ p is negative, the angle is turned clockwise. In other

words, the normal of one principal plane is rotated 17.5°

below the reference x axis. One of the in-plane principal

stresses—either σ p1 or σ p2 —acts on this principal plane. To

determine which principal stress acts at θ p = −17.5°, use the

following two-part rule:

• If the term σ x − σ y is positive, then θ p indicates the

orientation of σ p1 .

• If the term σ x − σ y is negative, then θ p indicates the

orientation of σ p2 .

Since σ x − σ y is positive, θ p indicates the orientation of σ p1 =

13.21 ksi. The other principal stress, σ p2 = −11.21 ksi, acts on

a perpendicular plane. The in-plane principal stresses are

shown on the element labeled “P” in the figure. Note that

there are never shear stresses acting on the principal planes.

7 ksi

9 ksi

11 ksi

Results sketched by using

the two-element format

The planes of maximum in-plane shear stress are always located 45° away from the

principal planes; therefore, θ s = 27.5°. Although Equation (12.15) gives the magnitude

of the maximum in-plane shear stress, it does not indicate the direction in which the

shear stress acts on the plane defined by θ s . To determine the direction of the shear stress,

solve Equation (12.4) for τ nt , using the values σ x = 11 ksi, σ y = −9 ksi, τ xy = −7 ksi, and

θ = θ s = 27.5°:

12.21 ksi

27.5°

x

17.5°

1 ksi

S

P

1 ksi

11.21 ksi

13.21 ksi

2 2

τ =−( σ − σ )sinθcos θ + τ (cos θ − sin θ)

nt x y xy

2 2

=−[(11 ksi) − ( − 9 ksi)]sin 27.5° cos 27.5 ° + ( − 7 ksi)[cos 27.5°− sin 27.5 ° ]

=−12.21 ksi

Since τ nt is negative, the shear stress acts in a negative t direction on a positive n face.

Once the shear stress direction has been determined for one face, the shear stress direction

is known for all four faces of the stress element. The maximum in-plane shear stress and

the average normal stress are shown on the stress element labeled “S.” Note that, unlike

the principal stress element, normal stresses will usually be acting on the planes of

maximum in-plane shear stress.

The principal stresses and the maximum in-plane

shear stress can also be reported on a single wedgeshaped

element, as shown in the accompanying sketch.

This format can be somewhat easier to use than the twoelement

sketch format, particularly with regard to the

direction of the maximum in-plane shear stress. The

maximum in-plane shear stress and the associated average

normal stress are shown on the sloped face of the

wedge, which is rotated 45° from the principal planes.

The shear stress arrow on this face always starts on the

σ p1 side of the wedge and points toward the σ p2 side of

the wedge. Once again, there is never a shear stress on the

principal planes (i.e., the σ p1 and σ p2 sides of the wedge).

7 ksi

9 ksi

11 ksi

(c) For plane stress, such as the example presented here, the z face is free of stress.

Therefore, τ zx = 0, τ zy = 0, and σ z = 0. Since the shear stress on the z face is zero, the

z face must be a principal plane with a principal stress σ p3 = σ z = 0. The absolute

maximum shear stress (considering all possible planes rather than simply those

Results sketched by using

the wedge element format.

1 ksi

x

17.5°

σp1 side of

12.21 ksi

the wedge

σ 13.21 ksi

p2 side of

the wedge

11.21 ksi

509

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!