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2J

Solving inequalities

105

Example 17

Solving inequalities

Solve the following inequalities.

a 5x + 2 < 47 b

SOLUTION

a 5x + 2 < 47

−2

−2

5x < 45

÷5 ÷5

x < 9

3 + 4x

9

≥ 3 c 15 − 2x > 1

EXPLANATION

The inequality is solved in the same way as an equation is

solved: 2 is subtracted from each side and then both sides

are divided by 5 . The sign does not change throughout.

b

3 + 4x

≥ 3

9

×9 ×9

3 + 4x ≥ 27

−3

−3

4x ≥ 24

÷4 ÷4

x ≥ 6

The inequality is solved in the same way as an equation is

solved. Both sides are first multiplied by 9 to eliminate 9

from the denominator.

c 15 − 2x > 1

−15

−15

−2x > −14

÷ −2 ÷ −2

x < 7

15 is subtracted from each side.

Both sides are divided by −2 . Because this is a negative

number, the inequality is reversed from > to < .

Exercise 2J

EXTENSION

UNDERSTANDING AND FLUENCY

1–4, 5–7(½) 4, 5–7(½), 8

5–7(½), 8

1 If x = 3 , classify the following inequalities as true or false.

a x + 4 > 2 b 5x ≥ 10

c 10 − x < 5 d 5x + 1 < 16

2 State whether the following choices of x make the inequality 2x + 4 ≥ 10 true or false.

a x = 5 b x = 1

c x = −5 d x = 3

3 a Copy and complete the following.

2x < 8

÷2 ÷2

x < __

b What is the solution to the inequality 2x < 8 ?

Cambridge Maths NSW

Stage 4 Year 8 Second edition

ISBN 978-1-108-46627-1 © Palmer et al. 2018

Cambridge University Press

Photocopying is restricted under law and this material must not be transferred to another party.

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