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182 Chapter 3 Measurement and Pythagoras’ theorem

Example 28

Applying Pythagoras to find a shorter side

A 10 m steel brace holds up a concrete wall. The bottom of the

brace is 5 m from the base of the wall. Find the height of the

concrete wall, correct to two decimal places.

10 m

Wall

5 m

SOLUTION

Let a metres be the height of the wall.

a 2 + b 2 = c 2

a 2 + 5 2 = 10 2

a 2 + 25 = 100

a 2 = 75

a = √75

= 8.66 (to 2 d.p.)

The height of the wall is 8.66 metres.

EXPLANATION

Choose a letter (pronumeral) for the unknown height.

Substitute into Pythagoras’ theorem.

Subtract 25 from both sides.

√75 is the exact answer.

Round as required.

Answer a worded problem using a full sentence.

Exercise 3M

UNDERSTANDING AND FLUENCY

1–4 2, 3–4(½)

3–4(½)

1 Write Pythagoras’ theorem for each given triangle.

a

b 5

m 9

p

10

c

15

w d

w

c

12

8

3

2 Copy and complete the missing steps.

a

15

9

a

a 2 + b 2 = c 2

a 2 + 9 2 = ___

a 2 + ___ = 225

a 2 = ___

∴ a = √______

= ___

b

b

25

a 2 + b 2 = c 2

7 2 + b 2 = ____

___ + b 2 = ___

b 2 = 576

∴ b = √______

= ___

7

Cambridge Maths NSW

Stage 4 Year 8 Second edition

ISBN 978-1-108-46627-1 © Palmer et al. 2018

Cambridge University Press

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