year 8 maths

648
Multiple-choice questions
1 B 2 D 3 C 4 A 5 B
6 E 7 A 8 E 9 A 10 E
Short-answer questions
1 a b
c
d
8 a i F ii G
b i EH
ii FG
c i ∠G
ii ∠E
9 a RHS b SAS c SSS d AAS
10 a x = 3, a = 25 b x = 5, a = 18
11 a ∠BAE = ∠DCE (alternate angles in parallel lines)
∠ABE = ∠CDE (alternate angles in parallel lines)
AB = CD (given)
∴ △ABE ≡ △CDE (AAS)
b AE = CE and BE = ED so AC and BD bisect each other.
12 a AE = CE, AB = CB and BE is common
∴ △ABE ≡ △CBE (SSS)
b ∠AEB = ∠CEB because △ABE ≡ △CBE
and since ∠AEB + ∠CEB = 180°
∠AEB = ∠CEB = 90° so AC and BD bisect at right angles.
e
f
Extended-response question
1 a A′(0, 1), B′(−2, 1), C′(−2, 4)
b A′(3, 1), B′(3, −1), C′(0, −1)
c A′(1, −1), B′(−1, −1), C′(−1, 2)
2 a A′(1, −2), B′(3, −4), C′(0, −2)
b A′(−1, 2), B′(−3, 4), C′(0, 2)
3 a 4 b 1 c 2 d 1
e 6 f 0
4 a [
1
4]
5 a
c
2
1
y
b [
3
−6]
−2 −1
O
−1
1 2
−2
2
1
y
−2 −1
O
−1
1 2
−2
x
x
c [
−3
−7]
b
2
1
y
−2 −1
O
−1
1
−2
d [
4
6]
2
x
Chapter 9
Pre-test
1 a 0, 1, 2, 4, 6, 7, 9, 10, 14 b 20, 30.6, 36, 100, 101, 204
c 1.2, 1.7, 1.9, 2.7, 3.2, 3.5
2 a Total = 40, average = 8
b Total = 94, average = 18.8
c Total = 3.3, average = 0.66
3 a 1 6
b 150° c i $420 ii $630
4 a 4 b 3 c Saturday
d 26 e 1 3
5 a 11
b 10, 11, 11, 12, 12, 12, 12, 13, 13, 14, 14
c
6 a 3 b 2
c no rotational symmetry
7 a
C
c
C
b
C
10 11 12 13 14
d 12 e 12.1 . 8 .
Exercise 9A
1 a C b D c A
d E e F f B
2 a categorical b numerical c numerical
d categorical e numerical f numerical
3 Answers will vary.
Cambridge Maths NSW
Stage 4 Year 8 Second edition
ISBN 978-1-108-46627-1 © Palmer et al. 2018
Cambridge University Press
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