morphological? - KOPS - Universität Konstanz
morphological? - KOPS - Universität Konstanz
morphological? - KOPS - Universität Konstanz
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(6) antepenult Penult<br />
iki Vki<br />
iki Vki<br />
transp. non transp. transp. non transp.<br />
cúbi[t]i elásti[t]i austría[t]i sínda[t]i antí[k]i ubriá[k]i<br />
Four words like opaco opacità, among which:<br />
(7) cié[k]o cié[k]i ce[t]itá<br />
‘blind-M SG’ ‘blind-M PL’ ‘blindness’<br />
méndi[k]o méndi[k]i mendi[t]itá<br />
‘beggar-M SG’ ‘beggar-M PL’ ‘beggarliness’<br />
Data from Google (October 2007):<br />
(8) opa[k]o opa[t]itá opa[k]issimo opa[t]issimo<br />
1.600.000 273.000 63 259<br />
cie[k]o ce[t]itá c(i)e[k]issimo c(i)e[t]issimo<br />
4.000.000 623.000 63 -<br />
As (8) shows, opacità is proportionally more frequent than cecità (a proportion of 5,8 vs. 6,4<br />
when compared to the underived word). The proportion is not particularly striking, but two<br />
facts may support this view: (i) cecità is very frequent in technical and medical texts, whereas<br />
opacità belongs more to the ordinary language. The quantity of texts including the word<br />
cecità is probably greater on the Web than in everyday life; (ii) other words derived from<br />
opaco display palatalization (cf. opacizzare, opacificare), while cecità is the only derivate<br />
from cieco displaying it: so to say, the “root” // seems more available than the “root”<br />
//.<br />
3. Stress assignment in Italian<br />
Generally, the quantity-based Latin stress algorithm is taken as a base (but cf. e.g. Vincent<br />
1988):<br />
stress on the antepenult, if there is one, and the penult is light, otherwise<br />
stress on the penult, if there is one<br />
(9) réx ‘king’<br />
rósa ‘rose’<br />
romnus ‘Roman’ *rómnus<br />
cucúrri ‘I ran’ *cúcurri<br />
póplus ‘people’ *poplus<br />
Loss of distinctive value for vocalic length. In Italian, heavy syllable = closed syllable. What<br />
is proposed is a reduced version of (9) (Mioni 1993, Bertinetto & Loporcaro 2002):<br />
stress on the antepenult, if there is one, and the penult is open, otherwise<br />
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