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Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

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90 CHAPTER 4<br />

This transformation shows that beta decay occurs among those nuclides that have a<br />

surplus of neutrons. For beta emission <strong>to</strong> be energetically possible, the exact nuclear<br />

mass of the parent must be greater than the sum of the exact masses of the daughter<br />

nucleus plus the beta particle.<br />

Mp = Md + Me + Q. (4.7)<br />

This restriction, of course, is analogous <strong>to</strong> the corresponding restriction on alpha<br />

emitters. Because a unit negative charge is lost during beta decay and the mass of the<br />

beta particle is ≪1 amu, the daughter nucleus is one a<strong>to</strong>mic number higher than<br />

its parent but retains the same a<strong>to</strong>mic mass number as the parent. For example,<br />

radioactive phosphorus decays <strong>to</strong> stable sulfur according <strong>to</strong> the equation<br />

32<br />

15<br />

P → 32<br />

16<br />

0<br />

S + −1e + 1.71 MeV.<br />

The transformation energy, in this instance 1.71 MeV, is the energy equivalent of<br />

the difference in mass between the 32 P nucleus and the sum of the masses of the<br />

32 S nucleus and the beta particle, and appears as kinetic energy of the beta particle.<br />

If neutral a<strong>to</strong>mic masses are used <strong>to</strong> complete the mass–energy equation, then, of<br />

course, the mass of the electron shown in the right-hand side of Eq. (4.7) is not<br />

considered since it is implicitly included in the extranuclear electronic structure of<br />

the 32 S. The mass difference is<br />

31.973907 = 31.972070 + Q<br />

Q = 0.001837 amu<br />

and the energy equivalent of the mass difference is<br />

0.001837 × 931 MeV/amu = 1.71 MeV.<br />

Examination of Eq. (4.5) shows that in the case of beta emission, an extremely<br />

small part of the energy of the reaction is dissipated by the recoil nucleus since m/M<br />

(where m is now the mass of the beta particle and M is the mass of the daughter<br />

nucleus) is very small. In the example given above,<br />

m 0.00055<br />

= = 0.000017<br />

M 32<br />

and Q is only 1.000017 times greater than the kinetic energy of the beta particle.<br />

On the basis of the above analysis, one might expect beta particles <strong>to</strong> be monoenergetic,<br />

as in the case of alpha radiation. This expectation is not confirmed<br />

by experiment. Instead, beta particles are found <strong>to</strong> be emitted with a continuous<br />

energy distribution ranging from zero <strong>to</strong> the theoretically expected value based on<br />

mass–energy considerations for the particular beta transition. In the case of 32 P, for<br />

example, although the maximum energy of the beta particle may be 1.71 MeV, most<br />

of the betas have considerably smaller kinetic energies, as shown in Figure 4-4. The<br />

average energy of a 32 P beta particle is 0.7 MeV or about 41% of the maximum energy.<br />

Generally, the average energy of the beta radiation from the most beta-active

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