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Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

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NONIONIZING RADIATION SAFETY 769<br />

in which the material <strong>to</strong> be heated is the dielectric. Most dielectric materials—such<br />

as ceramics, wood, paper, plastics, etc.—absorb energy when placed in an alternating<br />

electric field, because these “nonconduc<strong>to</strong>rs” exhibit some degree of conductivity<br />

as polar molecules rotate under the influence of the alternating electric field. The<br />

loss tangent, or the degree of lossiness of a dielectric material, is a measure of energy<br />

absorption by this mechanism. (Lossiness should not be confused with leakage of<br />

charge through an insulater, as in the case of the pocket dosimeter shown in Fig.<br />

6-2.) The degree of lossiness for any given material, as shown in Eq. (2.63), is a<br />

function of the frequency of the alternating electric field. Generally, the efficiency<br />

of dielectric heating is 50–60%. An application of industrial dielectric heating is<br />

given in the following example:<br />

W Example 14.22<br />

A <strong>to</strong>tal of 500 kg of resin-bonded sand cores are <strong>to</strong> be baked in a dielectric-core oven<br />

every hour. The sand mix contains 3% water, and resin that cures at 107 ◦ C. If the<br />

specific heat of the resin-sand mixture is 1250 J/kg/ ◦ C (0.3 Btu/lb/ ◦ F), the ambient<br />

temperature is 18 ◦ C, and the overall efficiency is 50%. Calculate<br />

(a) the power required <strong>to</strong> heat the water in the mixture from 18 ◦ C <strong>to</strong> 100 ◦ C<br />

(specific heat of water = 4178 J/kg/ ◦ C).<br />

(b) the power required <strong>to</strong> vaporize the water (latent heat of vaporization of water<br />

= 2.25 × 10 6 J/kg).<br />

(c) the power required <strong>to</strong> heat the sand–resin mixture from 18 ◦ C<strong>to</strong>107 ◦ C.<br />

(d) the <strong>to</strong>tal power required.<br />

Solution<br />

(a) The required power <strong>to</strong> heat the water in the mixture from 18 ◦ C<strong>to</strong>100 ◦ Cis<br />

P = 0.03 × 500 kg<br />

h (100◦C − 18 ◦ C) × 4178 J/kg<br />

◦C 1 hour<br />

J<br />

×<br />

= 1428<br />

3600 seconds s .<br />

(b) The required power <strong>to</strong> vaporize the water is<br />

P = 0.03 × 500 kg<br />

h × 2.25 × 106 J<br />

kg ×<br />

= 9375 J<br />

s .<br />

1 hour<br />

3600 seconds

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