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Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

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12 CHAPTER 2<br />

theory of relativity. According <strong>to</strong> Einstein, the relationship between mass and energy<br />

is<br />

E = mc 2 , (2.23)<br />

where E is the <strong>to</strong>tal energy of a piece of matter whose mass is m and c is the velocity of<br />

light in vacuum. The principle of relativity tells us that all matter contains potential<br />

energy by virtue of its mass. It is this energy source that is tapped <strong>to</strong> obtain nuclear<br />

energy. The main virtue of this energy source is the vast amount of energy that can be<br />

derived from conversion in<strong>to</strong> its energy equivalent of small amounts of nuclear fuel.<br />

W EXAMPLE 2.3<br />

(a) How much energy can be obtained from 1gofnuclear fuel?<br />

Solution<br />

E = mc 2 = 1 × 10 −3 kg ×<br />

<br />

3 × 10<br />

8 m2<br />

s<br />

= 9 × 10 13 J.<br />

Since there are 2.78 × 10 −7 kilowatt-hours (kW h) per joule, 1 g of nuclear fuel yields<br />

13 J<br />

kW · h<br />

7 kW · h<br />

E = 9 × 10 × 2.78 × 10−7 = 2.5 × 10<br />

g J<br />

g<br />

(b) How much coal, whose heat content is 13,000 Btu/lb, must be burned <strong>to</strong> liberate<br />

the same amount of energy as 1gofnuclear fuel?<br />

Solution<br />

1 Btu = 2.93 × 10 −4 kW h.<br />

Therefore, the amount of coal required is<br />

2.5 × 10 7 4 Btu<br />

kW · h<br />

kW · h = 1.3 × 10 × 2.93 × 10−4<br />

lb Btu<br />

3 lb<br />

×2 × 10 × C <strong>to</strong>ns<br />

<strong>to</strong>n<br />

Therefore,<br />

C = 3280 <strong>to</strong>ns (2981 metric <strong>to</strong>ns)<br />

The loss in mass accompanying ordinary energy transformations is not detectable<br />

because of the very large amount of energy released per unit mass and the

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