30.06.2013 Views

Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Elastic Collision<br />

REVIEW OF PHYSICAL PRINCIPLES 27<br />

An elastic collision is defined as a collision between two bodies in which kinetic<br />

energy and momentum are conserved; that is, the sum of the kinetic energy of the<br />

two bodies before the collision is equal <strong>to</strong> their sum after the collision, and the sums<br />

of their momenta before and after the collision are the same. In an elastic collision,<br />

the <strong>to</strong>tal kinetic energy is redistributed between the colliding bodies; one body gains<br />

energy at the expense of the other. A simple case is illustrated in the example below.<br />

W EXAMPLE 2.12<br />

A block of mass 10 kg, made of a perfectly elastic material, slides on a frictionless<br />

surface with a velocity of 2 m/s and strikes a stationary elastic block whose mass is<br />

2 kg (Fig. 2-8). How much energy was transferred from the large block (M) <strong>to</strong>the<br />

small block (m) during the collision?<br />

Solution<br />

If V1,v1, andV2 and v2 are the respective velocities of the large and small blocks<br />

before and after the collision, then, according <strong>to</strong> the laws of conservation of energy<br />

and momentum, we have<br />

and<br />

1 2 1<br />

MV1 +<br />

2 2 mv2<br />

1<br />

1 =<br />

2 MV 2 1<br />

2 +<br />

2 mv2 2<br />

MV1 + mv1 = MV2 + mv2<br />

Since v1 = 0, Eqs. (2.41) and (2.42) may be solved simultaneously <strong>to</strong> give<br />

V2 = 1 1 m<br />

3 s and v2 = 3 1 m<br />

3 s .<br />

The kinetic energy transferred during the collision is<br />

1 2 1<br />

MV1 −<br />

2 2 MV 2 2<br />

<br />

1<br />

= × 10 4 −<br />

2 16<br />

<br />

= 11<br />

9<br />

1<br />

9 J,<br />

(2.41)<br />

(2.42)<br />

Figure 2-8. Elastic collision between blocks M and m, in which the sum of both kinetic energy and<br />

momenta of the two blocks before and after the collision are the same.

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!