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Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

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When we combine the constants in Eq. (6.35), we have<br />

RADIATION DOSIMETRY 231<br />

˙D∞(air) = 4.45 × 10 −7 × Ca × Ē mGy/h. (6.36)<br />

Since the skin of a person in an infinite medium is irradiated from one side only,<br />

and since soft tissue absorbs about 10% more energy per kilogram than air does, the<br />

dose rate <strong>to</strong> the basal cells of the skin in a semi-infinite medium is<br />

˙Db = 0.5 × 1.1 × ˙D∞(air) × e −(μβ,t×0.007) . (6.37)<br />

If we combine Eqs. (6.36) and (6.37), we have the beta dose <strong>to</strong> the skin of a person<br />

immersed in a large cloud of concentration C Bq/m 3 :<br />

˙Db = 2.45 × 10 −7 × C × Ē × e −(μβ,t×0.007) mGy/h. (6.38)<br />

Generally, if there are fi betas of average energy Ēi MeV whose absorption coefficient<br />

is μβi,t each, then the beta dose rate is<br />

˙Db = 2.45 × 10 −7 × C <br />

i<br />

and if we divide by the concentration C , we obtain DCF:<br />

DCF (submersion) = 2.45 × 10 −7 × <br />

W Example 6.12<br />

fi Ēi × e −(μβi ,t×0.007) mGy<br />

, (6.39)<br />

h<br />

i<br />

fi Ē i × e −(μβi ,t×0.007) mGy/h<br />

. (6.40)<br />

Bq/m3 Calculate the dose rate <strong>to</strong> the skin of a person immersed in a large cloud of 85 Kr at<br />

a concentration of 37 kBq/m 3 (10 −6 μCi/mL).<br />

Solution<br />

Kryp<strong>to</strong>n-85 is a pure beta emitter that is transformed <strong>to</strong> 85 Rb by the emission of<br />

a beta particle whose maximum energy is 0.672 MeV and whose average energy is<br />

0.246 MeV. The tissue absorption coefficient is calculated with Eq. (6.21):<br />

μβ,t = 18.6(0.672 − 0.036) −1.37 = 34.6 cm 2 /g,<br />

and the skin dose is calculated with Eq. (6.38):<br />

˙Db = 2.45 × 10 −7 × C × Ē × e −(μβ,t×0.007) mGy/h<br />

˙Db = 2.45 × 10 −7 × 3.7 × 10 4 × 0.246 × e −(34.6×0.007)<br />

˙Db = 1.8 × 10 −3 mGy/h (0.18 mrads/h) .

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