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Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

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where<br />

C = cost per unit volume of the shield,<br />

A = area of the shield, and<br />

t = thickness of the shield.<br />

EXTERNAL RADIATION SAFETY 573<br />

The decreased radiation detriment due <strong>to</strong> the additional shielding, expressed as<br />

decreased collective dose, is given by<br />

S = ˙<br />

He −μt × f × N × τ, (10.44)<br />

where<br />

H ˙ = maximum dose-equivalent rate in the shielded area,<br />

f = ratio of the average <strong>to</strong> maximum dose rates in the shielded area,<br />

N = number of people in the shielded area,<br />

τ = lifetime of the shielded installation,<br />

μ = effective attenuation coefficient of shielding material, and<br />

t = thickness of the additional shielding.<br />

When we differentiate X and S with respect <strong>to</strong> the shield thickness t, we get<br />

and<br />

dX<br />

dt<br />

= C × A (10.45)<br />

dS<br />

dt = ˙<br />

H × f × N × τ(−μ)e −μt . (10.46)<br />

Substituting these two derivatives in<strong>to</strong> Eq. (10.42), we have<br />

CA= α × ˙<br />

H × f × N × τ × μe −μt<br />

(10.47)<br />

e −μt CA<br />

=<br />

. (10.48)<br />

α × H ˙ × f × N × τ × μ<br />

Equation (10.48) may be solved for t, the optimum shield thickness:<br />

<br />

<br />

CA<br />

1<br />

t = ln<br />

× . (10.49)<br />

α × H ˙ × f × N × τ × μ −μ

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