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Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

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V<br />

a<br />

b<br />

REVIEW OF PHYSICAL PRINCIPLES 25<br />

The electric intensity throughout the region between the two plates is ε new<strong>to</strong>ns<br />

per coulomb. The force acting on any charge within this field therefore is<br />

f = εq N. (2.36)<br />

If the charge q happens <strong>to</strong> be positive, then <strong>to</strong> move it across the distance d, from<br />

the negative <strong>to</strong> the positive plates, against the electric force in the uniform field<br />

requires the expenditure of energy given by the equation<br />

W = fd = εqd. (2.37)<br />

However, since potential difference (V ) is defined as work per unit charge,<br />

Eq. (2.37) may be expressed as<br />

or<br />

V = W<br />

q<br />

ε = V<br />

d<br />

= εd, (2.38)<br />

V<br />

. (2.39)<br />

m<br />

Equation (2.39) expresses electric field intensity in the units most commonly used<br />

for this purpose—volts per meter.<br />

A nonuniform electric field that is of interest <strong>to</strong> the health physicist (in instrument<br />

design) is that due <strong>to</strong> a potential difference applied across two coaxial conduc<strong>to</strong>rs,<br />

as shown in Figure 2-7. If the radius of the inner conduc<strong>to</strong>r is a meters and that of<br />

the outer conduc<strong>to</strong>r is b meters, then the electric intensity at any point between the<br />

two conduc<strong>to</strong>rs, r meters from the center, is given by<br />

ε = 1<br />

r ×<br />

ln<br />

V<br />

<br />

b<br />

a<br />

V<br />

, (2.40)<br />

m<br />

where V is the potential difference between the two conduc<strong>to</strong>rs.<br />

r<br />

Figure 2-7. Conditions for the nonuniform<br />

electric field between two coaxial<br />

conduc<strong>to</strong>rs given by Eq. (2.40).

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