30.06.2013 Views

Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

Introduction to Health Physics: Fourth Edition - Ruang Baca FMIPA UB

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

650 CHAPTER 12<br />

Note that in this case we used absorption cross sections for 2200 m s −1 neutrons,<br />

which leads <strong>to</strong> a conservative result when making criticality calculations for nuclear<br />

safety.<br />

The effective multiplication constant is useful for estimating the minimum concentration<br />

of a fissile material in a solution of modera<strong>to</strong>r that could become critical.<br />

W Example 12.4<br />

Estimate the minimum concentration of 93% enriched uranyl sulfate, UO2SO4, in<br />

water in order that the solution form a critical mass.<br />

Solution<br />

The minimum concentration will occur when the size (or volume) of the solution<br />

is infinitely large. In that case, in order <strong>to</strong> attain criticality,<br />

keff = ηεpf = 1.<br />

The value for η is calculated from Eq. (12.7), using the molar ratio of 0.27 : 3.66 from<br />

the table in example 12.3 for 238 N/ 235 N:<br />

549<br />

η =<br />

650 + 0.27<br />

× 2.5 = 2.11.<br />

× 2.8<br />

3.66<br />

To calculate f using Eq. (12.14), let us arrange the data as shown in the following<br />

table, letting M represent the number of moles of UO2SO4 that is <strong>to</strong> be added <strong>to</strong><br />

1 mol of water, <strong>to</strong> give the minimum concentration that will result in k∞ = 1. In<br />

Example 12.3, we calculated an a<strong>to</strong>mic ratio of 235U : U <strong>to</strong> be 3.66 : 3.93. Using this<br />

value gives the following:<br />

MATERIAL σa, BARNS MOLES σa × MOLES<br />

Uranium-235 650<br />

3.66<br />

M<br />

3.93<br />

605 M<br />

Uranium-238 2.8<br />

0.27<br />

M<br />

3.93<br />

0.192 M<br />

Water 0.664 1 0.664<br />

O2SO4 0.491 M 0.491M<br />

From the definition of f , Eq. (12.14), we have<br />

f =<br />

605M + 0.192M<br />

605M + 0.192M + 0.664 + 0.491M =<br />

605.2M<br />

605.7M + 0.664 .

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!