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Carsten Timm: Theory of superconductivity

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Thus the current flowing from left to right is<br />

∫ ∞<br />

I L→R ∝ 2e dω D<br />

h<br />

L(ω) s DR(µ n + ω + eV ) |t| 2 n F (ω) [1 − n F (ω + eV )]<br />

0<br />

{ ( √ ) (<br />

1 ω2 − ∆ 2 0<br />

× 1 +<br />

+ 1 √ )}<br />

ω2 − ∆ 2 0<br />

1 −<br />

2 ω 2 ω<br />

} {{ }<br />

= 1<br />

∫ 0<br />

+ 2e dω D<br />

h<br />

L(|ω|) s DR(µ n + ω + eV ) |t| 2 n F (ω) [1 − n F (ω + eV )]<br />

−∞<br />

{ ( √ ) (<br />

1 ω2 − ∆ 2 0<br />

× 1 −<br />

+ 1 √ )}<br />

ω2 − ∆ 2 0<br />

1 +<br />

2 |ω| 2 |ω|<br />

} {{ }<br />

= 1<br />

= 2e<br />

h<br />

∫ ∞<br />

−∞<br />

dω D s L(|ω|) D n R(µ + ω + eV ) |t| 2 n F (ω) [1 − n F (ω + eV )], (10.83)<br />

where DL s (ω) now is the superconducting density <strong>of</strong> states neither containing a spin factor <strong>of</strong> 2 nor the factor<br />

<strong>of</strong> 2 due describing both electrons and holes as excitations with positive energy—positive and negative energies<br />

are here treated explicitly and separately. We see that the electron-hole mixing does not lead to any additional<br />

factors beyond the changed density <strong>of</strong> states. With the analogous expression<br />

we obtain<br />

where<br />

Thus<br />

I R→L ∝ 2e<br />

h<br />

I sn ∝ 2e<br />

h<br />

∫ ∞<br />

−∞<br />

∫ ∞<br />

−∞<br />

dω D s L(|ω|) D n R(µ + ω + eV ) |t| 2 n F (ω + eV ) [1 − n F (ω)] (10.84)<br />

dω D s L(|ω|) D n R(µ + ω + eV ) |t| 2 [n F (ω) − n F (ω + eV )]<br />

∼= 2e<br />

h Dn L(E F ) D n R(E F ) |t| 2<br />

∫∞<br />

−∞<br />

dω Ds L (|ω|)<br />

D n L (E F ) [n F (ω) − n F (ω + eV )], (10.85)<br />

⎧<br />

⎪⎨<br />

DL s (|ω|)<br />

|ω|<br />

DL n(E F ) = √ for |ω| > ∆<br />

ω2 − ∆ 2 0 ,<br />

0<br />

⎪ ⎩<br />

0 for |ω| < ∆ 0 .<br />

I sn = G nn<br />

e<br />

∫ ∞<br />

−∞<br />

It is useful to consider the differential conductance<br />

G sn := dI sn<br />

dV<br />

= G nn<br />

∫ ∞<br />

−∞<br />

∫∞<br />

= G nn<br />

−∞<br />

(10.86)<br />

dω Ds L (|ω|)<br />

D n L (E F ) [n F (ω) − n F (ω + eV )]. (10.87)<br />

dω Ds L (|ω|)<br />

D n L (E F )<br />

(<br />

− ∂ n )<br />

F (ω + eV )<br />

∂ω<br />

dω Ds L (|ω|)<br />

D n L (E F ) β n F (ω + eV )[1 − n F (ω + eV )]. (10.88)<br />

100

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