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Carsten Timm: Theory of superconductivity

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The averaged current is just<br />

Ī =<br />

I c 2e<br />

Qω p V = C I c 2e<br />

2eI c RC V = V R . (11.49)<br />

Note that this result holds for any damping. It is evidently important to carefully specify whether a constant<br />

current or a constant voltage is imposed.<br />

11.3 Bogoliubov-de Gennes Hamiltonian<br />

It is <strong>of</strong>ten necessary to describe inhomogeneous systems, Josephson junctions are typical examples. So far, the only<br />

theory we know that is able to treat inhomogeneity is the Ginzburg-Landau theory, which has the disadvantage<br />

that the quasiparticles are not explicitly included. It is in this sense not a microscopic theory. We will now discuss<br />

a microscopic description that allows us to treat inhomogeneous systems. The essential idea is to make the BCS<br />

mean-field Hamiltonian spatially dependent. This leads to the Bogoliubov-de Gennes Hamiltonian. It is useful to<br />

revert to a first-quantized description. To this end, we introduce the condensate state |ψ BCS ⟩ as the ground state<br />

<strong>of</strong> the BCS Hamiltonian<br />

H BCS = ∑ kσ<br />

ξ k c † kσ c kσ − ∑ k<br />

∆ ∗ k c −k,↓ c k↑ − ∑ k<br />

∆ k c † k↑ c† −k,↓<br />

+ const. (11.50)<br />

|ψ BCS ⟩ agrees with the BCS ground state defined in Sec. 9.2 in the limit T → 0 (recall that ∆ k and thus H BCS<br />

is temperature-dependent). We have<br />

H BCS |ψ BCS ⟩ = E BCS |ψ BCS ⟩ , (11.51)<br />

where E BCS is the temperature-dependent energy <strong>of</strong> the condensate.<br />

Since H BCS is bilinear, it is sufficient to consider single-particle excitations. Many-particle excitations are<br />

simply product states, or more precisely Slater determinants, <strong>of</strong> single-particle excitations. We first define a<br />

two-component spinor<br />

( ) (<br />

|Ψk1 ⟩ c<br />

†<br />

)<br />

|Ψ k ⟩ ≡ :=<br />

k↑<br />

|ψ<br />

|Ψ k2 ⟩<br />

BCS ⟩ . (11.52)<br />

c −k,↓<br />

It is easy to show that<br />

With these relations we obtain<br />

H BCS |Ψ k1 ⟩ = H BCS c † k↑ |ψ BCS⟩ =<br />

[H BCS , c † k↑ ] = ξ k c † k↑ − ∆∗ k c −k,↓ , (11.53)<br />

[H BCS , c −k,↓ ] = −ξ k c −k,↓ − ∆ k c † k↑ . (11.54)<br />

(<br />

)<br />

ξ k c † k↑ − ∆∗ k c −k,↓ + c † k↑ H BCS |ψ BCS ⟩<br />

= (E BCS + ξ k ) |Ψ k1 ⟩ − ∆ ∗ k |Ψ k2 ⟩ (11.55)<br />

and<br />

H BCS |Ψ k2 ⟩ = H BCS c −k,↓ |ψ BCS ⟩ =<br />

(−ξ k c −k,↓ − ∆ k c † k↑ + c −k,↓ H BCS<br />

)<br />

|ψ BCS ⟩<br />

= (E BCS − ξ k ) |Ψ k2 ⟩ − ∆ k |Ψ k1 ⟩ . (11.56)<br />

Thus for the basis {|Ψ k1 ⟩ , |Ψ k2 ⟩} the Hamiltonian has the matrix form<br />

(<br />

EBCS + ξ k −∆ k<br />

−∆ ∗ k<br />

E BCS − ξ k<br />

)<br />

. (11.57)<br />

This is the desired Hamiltonian in first-quantized form, except that we want to measure excitation energies relative<br />

to the condensate energy. Thus we write as the first-quantized Hamiltonian in k space<br />

( )<br />

ξk −∆<br />

H BdG (k) =<br />

k<br />

−∆ ∗ . (11.58)<br />

k<br />

−ξ k<br />

113

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