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Carsten Timm: Theory of superconductivity

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It is instructive to first consider the normal state, for which ∆ k → 0. Then<br />

{<br />

0 for ξ k < 0,<br />

|u k | 2 = 1 2<br />

|v k | 2 = 1 2<br />

(<br />

1 + ξ )<br />

k<br />

|ξ k |<br />

(<br />

1 − ξ )<br />

k<br />

|ξ k |<br />

=<br />

1 for ξ k > 0,<br />

{<br />

1 for ξ k < 0,<br />

=<br />

0 for ξ k > 0.<br />

(10.30)<br />

(10.31)<br />

We see that the Bogoliubov quasiparticles described by γ, γ † , are holes for energies below the Fermi energy<br />

(ξ k < 0) and electrons for energies above (ξ k > 0). Their dispersion is E k = |ξ k |. For a parabolic normal<br />

dispersion ξ k :<br />

E k<br />

hole<br />

excitations<br />

electron<br />

excitations<br />

0 k F<br />

k<br />

The excitation energies E k are always positive except at the Fermi surface—it costs energy to create a hole in<br />

the Fermi sea and also to insert an electron into an empty √ state outside <strong>of</strong> the Fermi sea.<br />

Superconductivity changes the dispersion to E k = ξk 2 + |∆ k| 2 :<br />

E k<br />

∆ kF<br />

0 k F<br />

k<br />

Superconductivity evidently opens an energy gap <strong>of</strong> magnitude |∆ kF | in the excitation spectrum.<br />

We should recall that in deriving H BCS we have ignored a constant, which we now reinsert,<br />

H BCS = E BCS + ∑ kσ<br />

E k γ † kσ γ kσ. (10.32)<br />

The energy <strong>of</strong> the system is E BCS if no quasiparticles are present and is increased (by at least |∆ kF |) if quasiparticles<br />

are excited. The state without any quasiparticles is the pure condensate. Since E BCS depends on temperature<br />

through ⟨c −k,↓ c k↑ ⟩, the condensate is not generally the BCS ground state discussed previously. However, one can<br />

show that it agrees with the ground state in the limit T → 0.<br />

92

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