Carsten Timm: Theory of superconductivity
Carsten Timm: Theory of superconductivity
Carsten Timm: Theory of superconductivity
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we obtain<br />
(<br />
)<br />
2ξ k |u k | |v k | e i(β k−α k ) + |∆ k | |v k | 2 e i(2β k−ϕ k ) − |u k | 2 e i(ϕ k−2α k )<br />
= 0. (10.16)<br />
A special solution <strong>of</strong> this equation (we do not require the general solution) is given by<br />
From the last equation we obtain<br />
α k = 0, (10.17)<br />
β k = ϕ k , (10.18)<br />
(<br />
2ξ k |u k | |v k | + |∆ k | |v k | 2 − |u k | 2) = 0. (10.19)<br />
(<br />
4ξk 2 |u k | 2 |v k | 2 = |∆ k | 2 |v k | 4 − 2 |v k | 2 |u k | 2 + |u k | 4) (10.20)<br />
⇒<br />
(<br />
4 ξk 2 + |∆ k | 2) ( |u k | 2 |v k | 2 = |∆ k | 2 |v k | 4 + 2 |v k | 2 |u k | 2 + |u k | 4) ( = |∆ k | 2 |v k | 2 + |u k | 2) 2<br />
= |∆k | 2 (10.21)<br />
|∆ k |<br />
⇒ |u k | |v k | =<br />
(10.22)<br />
2<br />
√ξk 2 + |∆ k| 2<br />
so that<br />
|u k | 2 − |v k | 2 = 2ξ k |u k | |v k |<br />
|∆ k |<br />
=<br />
ξ k<br />
√ξ 2 k + |∆ k| 2 . (10.23)<br />
Together with |u k | 2 + |v k | 2 = 1 we thus find<br />
⎛<br />
⎞<br />
|u k | 2 = 1 ξ k<br />
⎝1 + √ ⎠ , (10.24)<br />
2<br />
ξk 2 + |∆ k| 2<br />
⎛<br />
⎞<br />
|v k | 2 = 1 ξ k<br />
⎝1 − √ ⎠ . (10.25)<br />
2<br />
ξk 2 + |∆ k| 2<br />
Restoring the phases in Eq. (10.22), we also conclude that<br />
∆ k<br />
u k v k =<br />
2<br />
√ξ . (10.26)<br />
k 2 + |∆ k| 2<br />
The BCS Hamiltonian now reads, ignoring a constant,<br />
⎛<br />
⎞<br />
H BCS = ∑ ⎝<br />
ξk<br />
2 √ + |∆ k | 2<br />
√ ⎠ ( )<br />
γ †<br />
k ξk 2 + |∆ k| 2 ξk 2 + |∆ k| 2 k↑ γ k↑ + γ † −k,↓ γ −k,↓<br />
= ∑ √ ( )<br />
ξk 2 + |∆ k| 2 γ † k↑ γ k↑ + γ † −k,↓ γ −k,↓ . (10.27)<br />
k<br />
Using ξ −k = ξ k and the plausible assumption |∆ −k | = |∆ k |, we obtain the simple form<br />
H BCS = ∑ kσ<br />
E k γ † kσ γ kσ (10.28)<br />
with the dispersion<br />
E k :=<br />
√<br />
ξ 2 k + |∆ k| 2 . (10.29)<br />
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