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Carsten Timm: Theory of superconductivity

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9<br />

Cooper instability and BCS ground state<br />

In this chapter we will first show that the attractive effective interaction leads to an instability <strong>of</strong> the normal<br />

state, i.e., <strong>of</strong> the Fermi sea. Then we will dicuss the new state that takes its place.<br />

9.1 Cooper instability<br />

Let us consider the scattering <strong>of</strong> two electrons due to the effective interaction.<br />

represented by the diagram<br />

k’<br />

, i ’<br />

ω n<br />

k’ + q, iω’ n + iν n<br />

A single scattering event is<br />

k,iω n<br />

k − q, iω n − iν n<br />

Electrons can also scatter multiple times:<br />

· · · + + + + · · · (9.1)<br />

An instability occurs if this series diverges since then the scattering becomes infinitely strong. In this case the<br />

perturbative expansion in the interaction strength V 0 represented by the diagrams breaks down. This means that<br />

the true equilibrium state cannot be obtained from the equilibrium state for V 0 = 0, namely the noninteracting<br />

Fermi gas, by perturbation theory. A state that is perturbatively connected to the free Fermi gas is called a<br />

Landau Fermi liquid. It is an appropriate description for normal metals. Conversely, a scattering instability<br />

signals that the equilibrium state is no longer a Fermi liquid.<br />

Like in the RPA, it turns out to be sufficient to consider the dominant diagrams at each order. These are<br />

the ladder diagrams, which do not contain crossing interaction lines. Moreover, the instability occurs first for<br />

the scattering <strong>of</strong> two electrons with opposite momentum, frequency, and spin. We thus restrict ourselves to the<br />

82

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