Carsten Timm: Theory of superconductivity
Carsten Timm: Theory of superconductivity
Carsten Timm: Theory of superconductivity
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∇ϕ − (q/c)A. Physics is invariant under the gauge transformation<br />
A → A + ∇χ, (6.59)<br />
Φ → Φ − 1 c<br />
˙χ, (6.60)<br />
ψ → e iqχ/c ψ, (6.61)<br />
where Φ is the scalar electric potential and χ(r, t) is an arbitrary scalar field. We make use <strong>of</strong> this gauge invariance<br />
by choosing<br />
χ = − c ϕ. (6.62)<br />
q<br />
Under this tranformation, we get<br />
A → A − c<br />
q ∇ϕ =: A′ , (6.63)<br />
ψ = (ψ 0 + δψ) e iϕ → (ψ 0 + δψ) e i(−ϕ+ϕ) = ψ 0 + δψ. (6.64)<br />
The macroscopic wave function becomes purely real (and positive). The Landau functional thus tranforms into<br />
∫ [<br />
F [δψ, A ′ ] → d 3 r − 2αδψ 2 + 1 ( ) ∗ <br />
2m ∗ i ∇δψ · <br />
i ∇δψ<br />
− α q 2<br />
β 2m ∗ c 2 (A′ ) ∗ · A ′ + 1<br />
]<br />
8π (∇ × A′ ) ∗ · (∇ × A ′ )<br />
(6.65)<br />
(note that ∇×A ′ = ∇×A). Thus the phase no longer appears in F ; it has been absorbed into the vector potential.<br />
Furthermore, dropping the prime,<br />
F [δψ, A] ∼ = ∑ [(−2α + 2 k 2 )<br />
2m ∗ δψkδψ ∗ k − α q 2<br />
β 2m ∗ c 2 A∗ k · A k + 1<br />
]<br />
8π (k × A k) ∗ · (k × A k )<br />
k<br />
= ∑ [(−2α + 2 k 2 )<br />
2m ∗ δψkδψ ∗ k − α q 2<br />
β 2m ∗ c 2 A∗ k · A k + k2<br />
8π A∗ k · A k − 1<br />
]<br />
8π (k · A∗ k)(k · A k ) . (6.66)<br />
k<br />
Obviously, amplitude fluctuations decouple from electromagnetic fluctuations and behave like for a neutral superfluid.<br />
We discuss the electromagnetic fluctuations further. The term proportional to α is due to <strong>superconductivity</strong>.<br />
Without it, we would have the free-field functional<br />
F free [A] = ∑ k<br />
1 [<br />
k 2 A ∗ k · A k − (k · A ∗<br />
8π<br />
k)(k · A k ) ] . (6.67)<br />
Decomposing A into longitudinal and transverse components,<br />
A k = ˆk(ˆk · A k ) + A k −<br />
} {{ }<br />
ˆk(ˆk · A k )<br />
} {{ }<br />
=: A ⊥ k<br />
=: A ∥ k<br />
(6.68)<br />
with ˆk := k/k, we obtain<br />
F free [A] = ∑ k<br />
= ∑ k<br />
1<br />
[<br />
(<br />
k 2 A ∥∗<br />
k<br />
8π · A∥ k + k2 A ⊥∗<br />
k · A ⊥ k −<br />
[✘✘✘✘ ✘<br />
1<br />
8π<br />
k 2 A ∥∗<br />
k<br />
· A∥ k + k2 A ⊥∗<br />
k<br />
k · A ∥∗<br />
k<br />
) ( )]<br />
k · A ∥ k<br />
· A ⊥ k − ✘ k 2 ✘✘✘<br />
A ∥∗ ✘ ]<br />
k · A∥ k<br />
= ∑ k<br />
1<br />
8π k2 A ⊥∗<br />
k · A ⊥ k . (6.69)<br />
Thus only the transverse components appear—only they are degrees <strong>of</strong> freedom <strong>of</strong> the free electromagnetic field.<br />
They do not have an energy gap.<br />
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