Carsten Timm: Theory of superconductivity
Carsten Timm: Theory of superconductivity
Carsten Timm: Theory of superconductivity
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Including the superconducting contribution, we get<br />
F [A] = ∑ [<br />
− α q 2<br />
β 2m ∗ c 2 A∥∗ k · A∥ k − α q 2<br />
β 2m ∗ c 2 A⊥∗ k · A ⊥ k + 1<br />
]<br />
8π k2 A ⊥∗<br />
k · A ⊥ k . (6.70)<br />
k<br />
All three components <strong>of</strong> A appear now, the longitudinal one has been introduced by absorbing the phase ϕ(r).<br />
Even more importantly, all components obtain a term with a constant coefficient, i.e., a mass term. Thus the<br />
electromagnetic field inside a superconductor becomes massive. This is the famous Anderson-Higgs mechanism.<br />
The same general idea is also thought to explain the masses <strong>of</strong> elementary particles, although in a more complicated<br />
way. The “Higgs bosons” in our case are the amplitude-fluctuation modes described by δψ. Contrary to what is<br />
said in popular discussions, they are not responsible for giving mass to the field A. Rather, they are left over<br />
when the phase fluctuations are eaten by the field A.<br />
The mass term in the superconducting case can be thought <strong>of</strong> as leading to the Meißner effect (finite penetration<br />
depth λ). Indeed, we can write<br />
F [δψ, A] = ∑ k<br />
(−2α + 2 k 2<br />
2m ∗ )<br />
δψ ∗ kδψ k + ∑ k<br />
[<br />
1 1<br />
8π λ 2 A∗ k · A k + k 2 A ∗ k · A k − (k · A ∗ k)(k · A k )]<br />
. (6.71)<br />
The photon mass is proportional to 1/λ. (To see that the dispersion relation is 2 ω 2 = m 2 c 4 + p 2 c 2 , we would<br />
have to consider the full action including a temporal integral over F and terms containing time-derivatives.)<br />
Elitzur’s theorem<br />
One sometimes reads that in the superconducting state gauge symmetry is broken. This is not correct. Gauge<br />
symmetry is the invariance under local gauge transformations. S. Elitzur showed in 1975 that a local gauge<br />
symmetry cannot be spontaneously broken. Rather, superconductors and superfluids spontaneously break a<br />
global U(1) symmetry in that the ordered state has a prefered macroscopic phase, as noted above.<br />
6.4 Type-I superconductors<br />
Superconductors with small Ginzburg-Landau parameter κ are said to be <strong>of</strong> type I. The exact condition is<br />
κ < 1 √<br />
2<br />
. (6.72)<br />
It turns out that these superconductors have a uniform state in an applied magnetic field, at least for simple<br />
geometries such as a thin cylinder parallel to the applied field.<br />
The appropriate thermodyamic potential for describing a superconductor in an applied magnetic field is the<br />
Gibbs free energy G (natural variable H) and not the Helmholtz free energy F (natural variable B), which we<br />
have used so far. They are related by the Legendre transformation<br />
∫<br />
G = F −<br />
d 3 r H · B<br />
4π . (6.73)<br />
For a type-I superconductor, the equilibrium state in the bulk is uniform (we will see later why this is not a<br />
trivial statement). The order parameter is then |ψ| = √ −α/β and the magnetic induction B as well as the vector<br />
potential (in the London gauge) vanish. Thus the Gibbs free-energy density is<br />
g s = f s = α |ψ| 2 + β 2 |ψ|4 = − α2<br />
β + β α 2<br />
2 β = − α2<br />
2β . (6.74)<br />
On the other hand, in the normal state ψ vanishes, but the field penetrates the system and B ≡ H so that<br />
g n = f n − HB<br />
4π = H2<br />
8π − H2<br />
4π = −H2 8π . (6.75)<br />
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