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Design and Stress Analysis of Extraterrestrial ... - The Black Vault

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a) b)<br />

c)<br />

Fig. 1.36.<br />

Determining thermal stresses.<br />

Before heating, the part is installed in a rigid housing which<br />

does not allow expansion during heating (Fig. 1.36b).<br />

Reactive<br />

force P occurs during heating. We find it from the thermal<br />

deformation, which is known; for this case it is equal to elastic<br />

deformation: ey = -et = -sAt. Hence P = eyEF.<br />

y<br />

<strong>Stress</strong>es <strong>and</strong> strains obtained in<br />

this state differ from actual<br />

ones since there is no rigid attachment <strong>of</strong> the part. To obtain<br />

true thermal deformations we must apply to the part load P,<br />

which<br />

occurs in the attachment <strong>of</strong> the part, but is directed in the opposite<br />

direction, i.e.,<br />

with negative sign (Fig. 1.36c).<br />

<strong>The</strong> sum <strong>of</strong> part deformations with rigid attachment (Fig. 1.36b)<br />

<strong>and</strong> deformations from reaction forces P, taken with opposite sign<br />

(Fig. 1.36c), gives tne true elastic deformation. Finally, we<br />

obtain<br />

ey = -uAt+ e(-P) - (1.5?)<br />

This method <strong>of</strong> finding elastic thermal deformation anu.<br />

consequently, stresses will be used in<br />

even more complex pi-vDlems.<br />

87

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