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Design and Stress Analysis of Extraterrestrial ... - The Black Vault

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qv2'0, .35. - 09.2.3. 1 (,-f)/ 2<br />

S i - 1.0-3 .10 daN/m 2 .<br />

This example shows that significant thermal stresses arise with<br />

comparatively small dimensions <strong>of</strong> the fuel element rod.<br />

Naturally an increase in the dimensions <strong>of</strong> the fuel element<br />

increases its thermal loading <strong>and</strong> can cause stresses which exceed<br />

the yield point. In this case, calculations should be performed<br />

with allowance for plastic flow.<br />

<strong>The</strong> physical picture <strong>of</strong> the stressed state will be as follows.<br />

Since the stresses exceed the yield point, plastic flow <strong>of</strong> the<br />

metal will occur in the fuel element core, due to which plastic<br />

deformations will appear <strong>and</strong> the excess thermal stresses will be<br />

relaxed. When the heat-releasing element is cooled, there will<br />

appear, in its core residual stresses <strong>of</strong> opposite sign which can also<br />

be called metal flow if the yield point is exceeded. Since the<br />

temperature field is axisymmetrical, the form <strong>of</strong> the fuel element<br />

remains unchanged, but its rupture resistivity will be weakened due<br />

to the cyl Lc nature <strong>of</strong> thelloading.<br />

In each individual case the stress level is determined by the<br />

degree <strong>of</strong> the fuel element's thermal intensity N Y. In low-power<br />

unstressed ieactors N < 1 kW/kg. After finding<br />

0<br />

ar o0, c<br />

", the<br />

strength <strong>of</strong> the fuel element core should be evaluated from formula<br />

(1.23)<br />

where<br />

0 Imat<br />

oi=

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