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Design and Stress Analysis of Extraterrestrial ... - The Black Vault

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<strong>The</strong> solution can be written in<br />

the form (3.66) or with transformation<br />

it can be similar for hyperbolic disks, in the form <strong>of</strong> (3.67)':<br />

I=a,•,. + CY-<br />

+ + (3.67")<br />

+a rd;<br />

J<br />

Coefficients a <strong>and</strong> 0, as for hyperbolic disks, depend on the geometric<br />

form, the disk material, <strong>and</strong> diameters D <strong>and</strong> D.. Numerical values<br />

<strong>of</strong> the coefficients are given in the form <strong>of</strong> nomograms where they<br />

are determined as a function <strong>of</strong> two arguments:<br />

t= DI<strong>and</strong> t- (see Fig. 3.33c).<br />

d<br />

d<br />

Graphs for determining coefficients a <strong>and</strong> 0 for conical disks are<br />

illustrated in Figs. 3.42-3.47. If the disks are not made <strong>of</strong> steel,<br />

coefficients a <strong>and</strong> B1, as for hyperbolic disks, must be multiplied<br />

by the ratio p/p CT In formulas (3.67') Td = (dn/10 6 )2, where<br />

d is the diameter <strong>of</strong> the complete cone in mm.<br />

In analyzing disks <strong>of</strong> hyperbolic <strong>and</strong> conic shapes we must assume<br />

that in the center <strong>of</strong> a disk without openings up to a certain<br />

diameter D < Da the thickness <strong>of</strong> the disk is constant (which usually<br />

is the case). Coefficients a <strong>and</strong> 0 for hyperbolic <strong>and</strong> conic disks<br />

are given for the arguments x = (D 1 )/(D) > 0.01 <strong>and</strong> t 1 = (D 1 )/(d) ><br />

0.01.<br />

Boundary conditions<br />

For disk analysis differential equations <strong>of</strong> the second order<br />

were obtained. <strong>The</strong>refore, in order to compute stresses we must<br />

have at least two boundary conditions.<br />

307

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