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30 CHAPTER 2. SOMMERFELD THEORY<br />

This means that a small shift in the Fermi energy, δE F gives rise to a change in the number<br />

density δn = g V (E F )δE F . The Fermi energy shift, in turn, is linked (via Eqn. 2.28) to V tot as<br />

δE F = e(δV + V ext ), from which we obtain<br />

δn = eg V (E F )(δV + V ext ) . (2.30)<br />

Linearised Thomas-Fermi. When the added potential V ext is small, the induced number<br />

density δn is small, and therefore the number density n cannot differ very much from the<br />

density n 0 <strong>of</strong> the system without the potential (n = n 0 + δn). We may then express Eqn.2.24<br />

in a linearised form with respect to the perturbing potential:<br />

∇ 2 δV (r) = e2 g V (E F )<br />

ɛ 0<br />

(δV (r) + V ext (r)) (2.31)<br />

Density response. This is solved by Fourier transforms, for instance by assuming an<br />

oscillatory perturbing potential V ext = V ext (q)e iqr and a resulting oscillatory induced potential<br />

δV = δV (q)e iqr :<br />

δV (q) = − e2 g V (E F )/ɛ 0<br />

V<br />

q 2 + e 2 ext (q) = − V<br />

g V (E F )/ɛ 0 q 2 + qT 2 ext (q) , (2.32)<br />

F<br />

where we have collected e 2 g V (E F )/ɛ 0 into the Thomas Fermi wave vector q T F = (e 2 g V (E F )/ɛ 0 ) 1 2<br />

,<br />

which for the free electron gas is calculated as<br />

q2 T F<br />

qT 2 F = 1 me 2<br />

π 2 ɛ 0 h¯ k 2 F = 4 k F<br />

= ( 2.95 √ Å −1 ) 2 . (2.33)<br />

π a B rs<br />

Here, a B = 4πh¯2ɛ 0<br />

≃ 0.53 Å is the Bohr radius and r<br />

me 2<br />

S is the Wigner-Seitz radius, defined by<br />

(4π/3)rS 3 = n−1 .<br />

For the induced number density we obtain:<br />

n ind (q) = ɛ 0q 2<br />

e<br />

V ext (q)<br />

[1 + q 2 /q 2 T F ] , (2.34)<br />

Dielectric permittivity. In general, this phenomenon is incorporated into electromagnetic<br />

theory through the generalised wavevector dependent dielectric function ɛ(q). The dielectric<br />

function relates the electric displacement D to the electric field E, in the form ɛ 0 ɛ(q)E(q) =<br />

D(q). While the gradient <strong>of</strong> the total potential V tot = V 0 + δV + V ext = δV + V ext (V 0 = 0<br />

for Jellium) gives the E− field, the gradient <strong>of</strong> the externally applied potential V ext gives the<br />

displacement field D. As E and D are related via the relative permittivity, ɛ, the potentials<br />

from which they derive are also connected by ɛ:<br />

V ext (q) = ɛ(q) (δV (q) + V ext (q)) (2.35)<br />

Using Eq. 2.32 we find<br />

q 2<br />

V tot (q) = V ext (q)<br />

q 2 + qT 2 F<br />

, (2.36)

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