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4.2. BLOCH’S THEOREM FROM DISCRETE TRANSLATIONAL SYMMETRY 57<br />
By taking out a factor e iqr , this can be rewritten as<br />
ψ q (r) = e iqr ∑ G<br />
c q−G e −iGr = e iqr u j,q (r)<br />
where the function u j,q (r) is built from periodic function e −iGr , and must therefore have<br />
the same periodicity as the lattice.<br />
This is Bloch’s theorem:<br />
Eigenstates <strong>of</strong> the one-electron Hamiltonian can be chosen to be a plane wave<br />
multiplied by a function with the periodicity <strong>of</strong> the Bravais lattice.<br />
4.2 Bloch’s theorem from discrete translational symmetry<br />
Another way <strong>of</strong> thinking about Bloch’s theorem is to consider what happens to an eigenstate<br />
<strong>of</strong> the Hamiltonian (kinetic energy plus periodic lattice potential), if it is translated in space.<br />
An arbitrary translation operation will not necessarily produce an eigenstate, because the new<br />
state, generated by this translation, may not match the lattice potential correctly. If the<br />
translation operation is matched to the lattice, however, so if it is a translation by a Bravais<br />
lattice vector, then the resulting state is also an eigenstate <strong>of</strong> the Hamiltonian. The reason<br />
for this lies in the connection between symmetry and quantum mechanics, which is discussed<br />
in quantum mechanics courses: if an operator (such as the Hamiltonian) is unchanged under<br />
a change <strong>of</strong> coordinate system (i.e. a symmetry operation such as translation, rotation, etc.),<br />
then applying a symmetry operation on the eigenstate <strong>of</strong> such an operator produces another<br />
eigenstate <strong>of</strong> the operator, with the same eigenvalue as the original one.<br />
Either the two eigenstates produced by the symmetry operation are actually the same and<br />
differ only by a complex prefactor, or they are different, in which case we are dealing with a<br />
set <strong>of</strong> degenerate eigenstates.<br />
In the first case, it is clear that the original eigenstate is also an eigenstate <strong>of</strong> the symmetry<br />
operation. In the second case, it can be shown that we can always choose from the subspace <strong>of</strong><br />
degenerate eigenstates a set <strong>of</strong> eigenstates which are also eigenstates <strong>of</strong> the symmetry operation.<br />
Lattices are symmetric under discrete translation <strong>of</strong> the coordinate system by lattice vectors.<br />
Accordingly, the eigenstates <strong>of</strong> the Hamiltonian can be chosen to be eigenstates <strong>of</strong> the discrete<br />
lattice translation operation. This is the underlying origin <strong>of</strong> Bloch’s theorem, which we will<br />
now explore in more detail.<br />
4.2.1 Symmetry in quantum mechanics – applied to the lattice<br />
Consider a symmetry operator ˆT, e.g. translation<br />
〈 〉<br />
r|ˆTψ = ψ(r + a).<br />
If the Hamiltonian Ĥ commutes with the symmetry operator ˆT, then this implies that ˆT<br />
maps one eigenstate <strong>of</strong> the Hamiltonian Ĥ onto another eigenstate <strong>of</strong> Ĥ with the same energy: