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Seed Health Management for Better Productivity - Govind Ballabh ...

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(<strong>Seed</strong> <strong>Health</strong> <strong>Management</strong> <strong>for</strong> <strong>Better</strong> <strong>Productivity</strong>)RAPD:RAPD’s are generated by using random sequence, ordinarily, 10 base long oligonucleotides asprimers <strong>for</strong> PCR amplification of genomic DNA extracted from different varieties. Polymorphism isproduced due to complementary sequence <strong>for</strong> the primer used being used in one strain (variety A)but not in the other ( variety B). As aresult an amplification product will be detectable as a band instrain A while strain B will not show the product. The F1 hybrid will two strains will show the bandwhile in F2 a 3:1 ratio will be obtained. Thus RAPD’s behave as dominant markers. Further thepresence of amplification product can be regarded as dominant allele and it’s absence asrecessive allele.RAPds have similar applications to those of RFLP. However they are faster andmore convenient to per<strong>for</strong>m than RFLP.Biotechnological tool <strong>for</strong> maintenance of hybridityBarnase-barstar system : Gene barnase encodes an RNAse which kills the cells in which it isexpressed by degrading RNA. The expression of barnase was confined to tapetal cells by fusing itwith the promoter of tobacco tapetum specific gene TA29 ( gene construct : pTA29- barnase; ppromoter ). When the chimaeric gene construct was transferred and expressed in tobacco andoilseed rape, the tapetal cells of anthers were destroyed and there was no pollen development.However there was no effect on female fertility. Since the male sterility due to barnase isdominant, the male sterile lines are always heterozygous (barnase/- ; the – sign indicates absenceof barnase gene in homologous chromosome) and they have to be maintained by crossing to anynormal, non trans<strong>for</strong>med male fertile line (-/-; barnase gene absent). Thus male sterile lines (barnase/-) will have to be crossed to be normal fertile lines (-/-), and only 50% of the progeny fromsuch crosses will be male sterile while rest 50% will be male fertile (-/-). In a hybrid seedproduction programme the male fertile plants present in male sterile line must be identifiedandeasily eliminated. This has been done by linking the barnase gene with the bar gene fromStreptomyces: bar gene confers resistance to herbicide phosphinothricin.When such male sterile(barnase-bar/-) plants are maintained by crossing with normal male fertile (-/-), all the male sterileprogeny ( barnase-bar/- ) are resistant to the herbicide, while all the male fertile plants (-/-) areherbicide susceptible. The male fertile plants are there<strong>for</strong>e eliminated by a herbicide spray at anearly stage of plant growth.The male fertility of barnase male steriles is restored by another gene, barstar, of thebacterium B.amyloliquefaciens. The gene barstar encodes a specific inhibitor of barnase encodedRNase. The barstar product <strong>for</strong>ms a higly stable 1:1 noncovalently bound complex with thebarnase RNase; this reaction provides protection to the bacterial cells from their own RNaseproduct. Transgenic plants expressing barstar are male fertile without any phenotypic effect, andare easily maintained in the homozygous state. When a homozygous barstar male fertile line iscrossed with a barnase male sterile all the progeny plants are male fertile since barstar geneproduct effectively inhibits the barnase RNAse in barnase-bar/barstar plants. This male- 175 -

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