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MEP-Technical Manual CDN 0408.qxd - Hambro

MEP-Technical Manual CDN 0408.qxd - Hambro

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DESIGN PRINCIPLES AND CALCULATIONS<br />

4.3.2 VARIOUS FLEXURE FAILURE STAGES<br />

t<br />

Joist depth “d”<br />

� 1 f’ c<br />

C f a<br />

Upon additional load application, the steel and concrete<br />

strains progress further into their inelastic ranges. The<br />

strain neutral axis continues to rise and the lever arm<br />

continues to increase as the centroid of compression force<br />

continues to rise. In (c), final failure occurs with crushing of<br />

the upper concrete fibres. At this point, the maximum fever<br />

arm e’, has been reached. In load capacity calculations, the<br />

simplified concrete stress block as shown in (c) is universally<br />

used.<br />

According to CAN3-S16.1-M01 (cl.17.9.3) and CSA A23.3-04<br />

(cl.10.1.7), the factored resisting moment of the composite<br />

section is given by:<br />

M rc = ø s A s F y e’ = T r e’<br />

Strain line<br />

T u = A s F y<br />

(a)<br />

Initial steel yield<br />

� 1 f’ c<br />

Where e’ = d + slab thickness – a/2 – y<br />

d = joist depth<br />

a = T r / � 1 ø c f’ c b e<br />

ø s = steel performance factor = 0.90<br />

A s = area of bottom chord<br />

y = neutral axis of bottom chord<br />

E y<br />

T u = A s F y<br />

Elastic<br />

strain<br />

E y<br />

� 1 ø c f’ c<br />

Simplified<br />

concrete<br />

stress block<br />

Inelastic strain<br />

(b)<br />

Secondary yield stages<br />

C u<br />

f’ c<br />

e’<br />

Fig. 13<br />

Elastic<br />

strain<br />

Fy = yield point of steel<br />

øc = concrete performance factor = 0.65<br />

f’ c = concrete compressive strength<br />

be = effective width of concrete top flange<br />

= the lesser of - joist spacing, or<br />

- span /4.<br />

Note: To determine the total allowable service load W s<br />

(see load tables), we convert the factored moment<br />

into a factored linear loading.<br />

Mf = Wf L2 (single span moment)<br />

8<br />

W f = 8 M f<br />

L 2<br />

And<br />

C<br />

T u = A s F y<br />

Inelastic strain<br />

(c)<br />

Ultimate stage<br />

W s = (W f - 1.25 D) + D<br />

1.5<br />

Where D = weight of (slab + joist)<br />

11

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