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MEP-Technical Manual CDN 0408.qxd - Hambro

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DESIGN PRINCIPLES AND CALCULATIONS<br />

4.6 DIAPHRAGM DESIGN<br />

4.6.1 THE HAMBRO SLAB AS A DIAPHRAGM<br />

With the increasing use of the <strong>Hambro</strong> system for floor of<br />

buildings in earthquake prone areas such as Anchorage,<br />

Los Angeles, Vancouver, Montreal and Quebec City or in<br />

hurricane prone areas such as Florida as well as for multistorey<br />

buildings where shear transfer could occur at some<br />

level of the building due to the reduction of the floor plan,<br />

it is important to develop an understanding of how the<br />

slabs will be able to transmit horizontal loads while being<br />

part of the <strong>Hambro</strong> floor system.<br />

The floor slab, part of the <strong>Hambro</strong> system, must be designed<br />

by the project structural engineer as a diaphragm to resist<br />

horizontal loads and transmit them to the vertical bracing<br />

system.<br />

Any diaphragm has the following limit states:<br />

1) Shear strength between the supports<br />

2) Out of plane buckling<br />

3) In plane deflection of the diaphragm<br />

4) Shear transmission at the supports<br />

A diaphragm works as the web of a beam spanning<br />

between or extending beyond the supports. In the case of<br />

a floor slab, the slab is the web of the beam spanning<br />

between or extending beyond the vertical elements<br />

designed to transmit to the foundations the horizontal<br />

loads produced by earthquake or wind.<br />

We will use a simple example of wind load acting on a<br />

diaphragm part of a horizontal beam forming a single span<br />

between end walls. The structural engineer responsible for<br />

the design of the building shall establish the horizontal<br />

loads that must be resisted at each floor of the building for<br />

the wind and earthquake conditions prevailing at the building<br />

location. The structural engineer must also identify the<br />

vertical elements that will transmit the horizontal loads to<br />

the foundations in order to calculate the shear that must be<br />

resisted by the floor slab.<br />

4.6.2 SHEAR STRENGTH BETWEEN SUPPORTS<br />

A series of fourteen specimens of concrete slabs, part of a<br />

<strong>Hambro</strong> floor system, were tested in the laboratories of<br />

Carleton University in Ottawa. The purpose of the tests was<br />

to identify the variables affecting the in plane shear strength<br />

of the concrete slab reinforced with welded wire mesh.<br />

The specimens were made of slabs with a concrete thickness<br />

of 63 mm (2.5”) or 70 mm (2.75”) forming a beam with<br />

a span of 610 mm (24”) and a depth of 610 mm (24”). This<br />

beam was loaded with two equal concentrated loads at<br />

152 mm (6”) from the supports. The other variables were:<br />

1) The size of the wire mesh<br />

2) The presence or absence of the <strong>Hambro</strong> joist embedded<br />

top chord parallel to the load in the shear zone<br />

3) The concrete strength<br />

It was found that the shear resistance of the slab is minimized<br />

when the shear stress is parallel to the <strong>Hambro</strong> joist<br />

embedded top chord. A conservative assumption could be<br />

made that the concrete confined steel wire mesh is the<br />

only element that will transmit the shear load over the<br />

embedded top chord.<br />

In the following example of the design procedure, we will<br />

take into account that the steel of the wire mesh is already<br />

under tension stresses produced by the continuity of the<br />

slab over the <strong>Hambro</strong> joist, and that the remaining<br />

capacity of the steel wire mesh will be the limiting factor<br />

for the shear strength of the slab.<br />

The largest bending moment is over the embedded<br />

top chord and is calculated for one meter width. In using<br />

the example from section 4.1.5 page 5, the non factored<br />

moment is:<br />

Dead load*: Mfd = 3KPa x (1.2m) 2 / 10 = 0.43 kN•m<br />

Live load*: MfL = 2KPa x (1.2m) 2 / 10 = 0.29 kN•m.<br />

1) Loads<br />

Factored dead load: 1.25 x 3.0 = 3.75 kPa<br />

Factored live load: 1.50 x 2.0 = 3.00 kPa<br />

Factored total load: 6.75 kPa<br />

And thus the factored live load accounts for 44% of the<br />

factored total load.<br />

2) Bending moment in the slab between joists due to<br />

gravity loads<br />

The smallest lever arm between the compression concrete<br />

surface and the tension steel of the wire mesh is also over<br />

the embedded top chord. This dimension allows us to<br />

calculate the factored bending capacity of the slab to be<br />

Mr = 1.61 kN•m*.<br />

To establish the shear capacity of steel wire mesh for a slab<br />

unit width of one meter, we use the following formula<br />

adapted from CSA A23.3-04 clause 11.5 and simplified<br />

to calculate the resistance of the reinforcing steel only,<br />

considering a shear crack developing at a 45 degree angle<br />

and intersecting the wire mesh in both directions.<br />

V r = ø s x A s x F y x cos (45°)<br />

= 0.85 x 2 x 123 x 400 x 0.707/1 000<br />

= 59.1 kN for a meter width of slab<br />

* See page 5 for calculation.<br />

15

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