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Direct Energy, 2018a

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102 6.2 The Wave and Particle Natures of Light<br />

small chunk, of light. A related quantityis a phonon, which is a quanta,<br />

or small chunk, of lattice vibrations. We will discuss phonons in a later<br />

section, and theydo not relate to light. Although, phonons can perturb<br />

light, and that is the basis for acousto-optic devices. The second wayto<br />

understand light is to think of it as a wave with a wavelength λ measured<br />

in nm. White light has a broad bandwidth while the light produced bya<br />

laser has a verynarrow bandwidth.<br />

These two descriptions of light complement each other. A photon is the<br />

smallest unit of light, and it has a particular wavelength. The energyof a<br />

photon of light with wavelength λ is given by<br />

E = hf = hc<br />

λ . (6.1)<br />

The quantity h is called the Planck constant, and it has a tinyvalue,<br />

h =6.626 · 10 −34 J · s. The quantity c is the speed of light in free space,<br />

c =2.998 · 10 8 m s .<br />

In SI units, energyis measured in joules. However, other units are sometimes<br />

used byoptical engineers because the energyof an individual photon<br />

is tinycompared to a joule. Another unit that is used is the electronvolt,<br />

or eV. The magnitude of the charge of an electron is q =1.602 · 10 −19 C.<br />

The electronvolt is the energyacquired bya charge of this magnitude in<br />

the presence of a voltage dierence of one volt [68, p. 8]. <strong>Energy</strong>in joules<br />

and energyin eV are related bya factor of q.<br />

E [J]<br />

= q · E [ eV]<br />

(6.2)<br />

Equations 6.1 and 6.2 can be combined to relate the energyof a photon in<br />

eV and the corresponding wavelength in nm.<br />

1240<br />

λ [nm]<br />

= E [ eV] . (6.3)<br />

Sometimes, energyis specied in the unit of wave number, cm −1 , which<br />

represents the reciprocal of the wavelength of the corresponding photon.<br />

<strong>Energy</strong>in joules and energyin wave number are related by<br />

E [ J] = hc<br />

λ<br />

E [ J] = 6.626 · 10−34 J · s · 2.998 · 10 8 m s<br />

λ [cm]<br />

· 100 cm m<br />

(6.4)<br />

(6.5)<br />

E [ J] =1.986 · 10−23 E [ cm −1 ] . (6.6)

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