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Direct Energy, 2018a

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13 THOMAS FERMI ANALYSIS 303<br />

We know something about the wave vectors of lled states in reciprocal<br />

space. At T =0K, the lowest states are lled, and all others are empty,<br />

and they are lled up to a radius of k f . The volume of a sphere of radius<br />

k f is given by 4 3 πk3 f , and this represents the number of lled k states per<br />

volume of reciprocal space. We can therefore simplify the expression above.<br />

ρ ch = −2q · 4<br />

3 πk3 f ·<br />

1<br />

(2π) 3 (13.50)<br />

ρ ch = −q<br />

3π 2 k3 f (13.51)<br />

( ) −3π<br />

2 1/3<br />

k f = ρ ch (13.52)<br />

q<br />

We want to write E kinetic e<br />

as a function of generalized path V .Wecan<br />

V<br />

now achieve this task by combining Eqs. 13.47 and 13.52.<br />

E kinetic e<br />

V<br />

( )<br />

= −32 −3π<br />

2 2/3<br />

10mq ρ ch ρ ch (13.53)<br />

q<br />

E kinetic e<br />

V<br />

= −32<br />

10mq<br />

( −3π<br />

2<br />

q<br />

) 2/3<br />

ρ 5/3<br />

ch<br />

(13.54)<br />

Electrical energy is the product of charge and voltage. More specically,<br />

from Eq. 2.8, it is given by<br />

E = 1 QV. (13.55)<br />

2<br />

Electrical energy density is then given by<br />

E<br />

V = 1 2 ρ chV. (13.56)<br />

Use Eq. 13.56 to relate ρ ch and V .<br />

E kinetic e<br />

V<br />

= 1 2 ρ chV = −32<br />

10mq<br />

( −3π<br />

2<br />

q<br />

) 2/3<br />

ρ 5/3<br />

ch<br />

(13.57)<br />

We have now related the generalized path and the generalized potential.<br />

ρ ch =<br />

V = −32<br />

5mq<br />

(<br />

−5mq<br />

3 2 ·<br />

( −3π<br />

2<br />

q<br />

) 2/3<br />

ρ 2/3<br />

ch<br />

(13.58)<br />

( ) )<br />

−3π<br />

2 −2/3 3/2<br />

V 3/2 (13.59)<br />

q

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