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Direct Energy, 2018a

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13 THOMAS FERMI ANALYSIS 301<br />

the wave vector | −→ k | of the electrons in the atom.At T =0K, electrons<br />

occupy the lowest allowed energy states.<strong>Energy</strong> states are occupied up to<br />

some highest occupied state called the Fermi energy E f .While electrical<br />

engineers use the term Fermi energy, chemists sometimes use the term<br />

chemical potential μ chem . The lowest energy states, are occupied while the<br />

higher ones are empty.Similarly, wave vectors are occupied up to some<br />

highest occupied wave vector called the Fermi wave vector k f .<br />

| −→ k | =<br />

{<br />

lled state<br />

˜r k f<br />

(13.36)<br />

The Fermi energy and the Fermi wave vector are related by<br />

E f = 2 kf<br />

2<br />

2m . (13.37)<br />

We use the idea of reciprocal space to write an expression for the kinetic<br />

energy of the electrons per unit volume [136, p.49].The kinetic energy<br />

due to any one electron as a function of position in reciprocal space is<br />

given by Eq.13.35.Note that at each value of | −→ k | =˜r, the electron has<br />

a dierent kinetic energy.To nd the kinetic energy per unit volume due<br />

to all electrons, we integrate over all | −→ k | =˜r in spherical coordinates that<br />

are occupied by electrons, and then we divide by the volume occupied in<br />

−→ k space.<br />

E kinetic e<br />

V<br />

1<br />

=<br />

vol.occupied in k space<br />

· ´lled<br />

( Ekinetic e<br />

) ( )<br />

e<br />

k levels −<br />

e − volume<br />

d (vol.all k space)<br />

(13.38)<br />

The number of electrons per unit volume is given by<br />

( ) e<br />

−<br />

volume<br />

= −ρ ch<br />

. (13.39)<br />

q<br />

The volume occupied in reciprocal space is 4 3 πk3 f , the volume of a sphere<br />

of radius k f .<br />

E kinetic e<br />

V<br />

= 1<br />

4<br />

3 πk3 f<br />

ˆ<br />

( 2˜r 2<br />

·<br />

lled k levels 2m<br />

)(<br />

−ρch<br />

A dierential element of the volume is expressed as<br />

q<br />

)<br />

d (vol.all k space)<br />

(13.40)<br />

d 3 ∣ ∣∣ −→ k<br />

∣ ∣∣ =˜r 2 sin ˜θ d˜r d˜θ d˜φ. (13.41)

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