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View File - University of Engineering and Technology, Taxila

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To have a feel for this expression, an illustration in the form <strong>of</strong> Example 3.5will be examined after the concept <strong>of</strong> channel capacity has been introduced.Channel Capacity. Channel capacity is the maximum value <strong>of</strong> mutualinformation IðY ; X Þ. As an illustration, the BSC as the DMC in Fig. 3.21 isused to evaluate the channel capacity. The average information transferred isgiven by (3.71). The output entropy isHðY Þ¼ PN¼2j¼1pðy j Þ log 21pðy j Þ¼ pðy 1 Þ log 21pðy 1 Þ þ pðy 2Þ log 21pðy 2 Þð3:81ÞBy allowing the crossover probabilities to be equal ðpðy 1 j x 2 Þ¼pðy 2 j x 1 Þ¼aÞ <strong>and</strong> the states probabilities to be pðx 1 Þ¼b <strong>and</strong> pðx 2 Þ¼ð1 bÞ, we can write the receiving self-probability using (3.68) aspðy 1 Þ¼ð1 aÞb þ að1 bÞ ð3:82ÞTherefore, pðy 2 Þ¼1pðy 1 Þ. So, the output entropy becomesHðY Þ¼Oðpðy 1 ÞÞ ¼ Oðb þ a 2abÞ ð3:83ÞFollowing the iterative approach, we can show that the conditional outputentropy isHðY j X Þ¼OðaÞð3:84Þwhere Oð Þis a functional abstract term. This expression depends on the noisein the channel. Substituting (3.83) <strong>and</strong> (3.84) in (3.71), the BSC averagemutual information isIðX ; Y Þ¼Oðb þ a 2abÞ OðaÞ ð3:85ÞIn real life a channel is fixed <strong>and</strong> the channel’s noise is difficult to control. Theobjective, therefore, will be to maximize the first Oð Þ-term, the nonnoisecomponent term, on the right-h<strong>and</strong> side <strong>of</strong> (3.85). It was noticed in Fig. 3.20that the entropy HðbÞ is maximum when the symbols’ source probabilities areequally probable; that is, b ¼ 0:5. Therefore, we want the nonnoise component<strong>of</strong> (3.85) to be0:5 ¼ðb þ a 2abÞ ð3:86ÞCopyright © 2002 by Marcel Dekker, Inc. All Rights Reserved.

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