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Spectral Theory in Hilbert Space

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11. STURM-LIOUVILLE EQUATIONS 79<br />

Proof. By Lemma 11.12, 〈Etu, v〉 = t<br />

−∞<br />

〈Rλu, v〉 =<br />

∞<br />

−∞<br />

d〈Etu, v〉<br />

t − λ =<br />

∞<br />

−∞<br />

By properties of the resolvent<br />

Rλu 2 =<br />

1<br />

2i Im λ 〈Rλu − R λ u, u〉 =<br />

û(t)ˆv(t) dρ(t)<br />

t − λ<br />

∞<br />

−∞<br />

ûˆv dρ, so that<br />

= 〈û(t)/(t − λ), ˆv(t)〉ρ.<br />

d〈Etu, u〉<br />

|t − λ| 2 = û(t)/(t − λ)2 ρ.<br />

Sett<strong>in</strong>g v = Rλu and us<strong>in</strong>g Lemma 11.12, it therefore follows that<br />

û(t)/(t−λ) 2 ρ = 〈û(t)/(t−λ), F(Rλu)〉ρ = F(Rλu) 2 ρ. It follows that<br />

we have û(t)/(t − λ) − F(Rλu)ρ = 0, which was to be proved. <br />

Lemma 11.15. The generalized Fourier transform is unitary from<br />

L 2 (a, b) to L 2 ρ and the <strong>in</strong>verse transform is the <strong>in</strong>verse of this map.<br />

Proof. Accord<strong>in</strong>g to Lemma 11.13 we need only show that if<br />

û ∈ L2 ρ has <strong>in</strong>verse transform 0, then û = 0. Now, accord<strong>in</strong>g to<br />

Lemma 11.14, F(v)(t)/(t − λ) is a transform for all v ∈ L2 (a, b) and<br />

non-real λ. Thus we have 〈û(t)/(t − λ), F(v)(t)〉ρ = 0 for all non-real λ<br />

if û is orthogonal to all transforms. But we can view this scalar product<br />

as the Stieltjes-transform of the measure t<br />

ûF(v) dρ, so apply<strong>in</strong>g the<br />

−∞<br />

<strong>in</strong>version formula Lemma 6.5 we have <br />

ûF(v) dρ = 0 for all compact<br />

K<br />

<strong>in</strong>tervals K, and all v ∈ L2 (a, b). Thus the cutoff of û, which equals<br />

û <strong>in</strong> K and 0 outside, is also orthogonal to all transforms, i.e., has<br />

<strong>in</strong>verse transform 0 accord<strong>in</strong>g to Lemma 11.13. It follows that<br />

<br />

v(x) = û(t)ϕ(x, t) dρ(t)<br />

K<br />

is the zero-element of L2 (a, b) for any compact <strong>in</strong>terval K. Differentiat<strong>in</strong>g<br />

under the <strong>in</strong>tegral sign we also see that v ′ (x) = <br />

K ûϕ′ (x, ·) dρ<br />

is the zero element of L2 (a, b). But these functions are cont<strong>in</strong>uous, so<br />

they are po<strong>in</strong>twise 0. Now 0 = v ′ (a) cos α − v(a) s<strong>in</strong> α = <br />

û dρ. Thus<br />

K<br />

û dρ is the zero measure, so that û = 0 as an element of L2 ρ. <br />

Lemma 11.16. If u ∈ D(T ), then F(T u)(t) = tû(t). Conversely, if<br />

û and tû(t) are <strong>in</strong> L 2 ρ, then F −1 (û) ∈ D(T ).<br />

Proof. We have u ∈ D(T ) if and only if u = Rλ(T u − λu), which<br />

holds if and only if û(t) = (F(T u)(t) − λû(t))/(t − λ), i.e., F(T u)(t) =<br />

tû(t), accord<strong>in</strong>g to Lemmas 11.14 and 11.15. <br />

This completes the proof of Theorem 11.8. We also have the follow<strong>in</strong>g<br />

analogue of Corollary 11.4.

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