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Spectral Theory in Hilbert Space

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1. ASYMPTOTICS OF THE m-FUNCTION 85<br />

as λ → ∞ along any non-real ray 1 . Similarly, for 0 < α < π,<br />

mα(λ) = cot α + ( √ −λ s<strong>in</strong> 2 α) −1 + o(|λ| −1/2 )<br />

as λ → ∞ along any non-real ray.<br />

By a non-real ray we always mean a half-l<strong>in</strong>e start<strong>in</strong>g at the orig<strong>in</strong><br />

which is not part of the real l<strong>in</strong>e. Here and later the square root is<br />

always the pr<strong>in</strong>cipal branch, i.e., the branch with a positive real part<br />

Now note that, up to constant multiples, the Weyl solution ψ is<br />

determ<strong>in</strong>ed by the boundary condition at b. For α = 0 we have<br />

ψ ′ (0, λ)/ψ(0, λ) = m0(λ), so keep<strong>in</strong>g a fixed boundary condition at b<br />

we obta<strong>in</strong> m0(λ) = (s<strong>in</strong> α+mα(λ) cos α)/(cos α−mα(λ) s<strong>in</strong> α). Solv<strong>in</strong>g<br />

for mα gives<br />

mα(λ) = cos α m0(λ) − s<strong>in</strong> α<br />

s<strong>in</strong> α m0(λ) + cos α<br />

= cot α − (m0(λ) s<strong>in</strong> 2 α) −1 +<br />

cos α<br />

m0(λ) s<strong>in</strong> 2 α(m0(λ) s<strong>in</strong> α + cos α) .<br />

Thus, the formula for m0 immediately implies that for mα, 0 < α < π,<br />

so that we only have to prove the formula for m0. This will require<br />

good asymptotic estimates of the solutions ϕ and θ.<br />

Lemma 12.3. If u solves −u ′′ + qu = λu with fixed <strong>in</strong>itial data <strong>in</strong> 0<br />

one has<br />

(12.4) u(x) = u(0)(cosh(x √ −λ) + O(1)(e x<br />

0 |q|/√ |λ| − 1)e x √ −λ )<br />

uniformly <strong>in</strong> x, λ.<br />

+ u′ (0)<br />

√ −λ (s<strong>in</strong>h(x √ −λ) + O(1)(e x<br />

0 |q|/√ |λ| − 1)e x √ −λ ),<br />

Proof. Solv<strong>in</strong>g the equation u ′′ + λu = f and then replac<strong>in</strong>g f by<br />

qu gives<br />

(12.5) u(x) = cosh(kx)u(0) + s<strong>in</strong>h(kx)<br />

k<br />

+<br />

u ′ (0)<br />

x<br />

where we have written k for √ −λ. Sett<strong>in</strong>g<br />

0<br />

s<strong>in</strong>h(k(x − t))<br />

q(t)u(t) dt,<br />

k<br />

g(x) = |u(x) − cosh(kx)u(0) − s<strong>in</strong>h(kx)<br />

u<br />

k<br />

′ −x Re k<br />

(0)|e<br />

1 If g is a positive function the notation f(λ) = o(g(λ)) as λ → ∞ means<br />

f(λ)/g(λ) → 0 as λ → ∞.

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