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PENELOPE 2003 - OECD Nuclear Energy Agency

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C.1. Tracking particles in vacuum. 227<br />

expressed in the form (adapted from Bielajew, 1988)<br />

r(t) = r 0 + tv 0⊥ + 1 a<br />

[<br />

cosh (act) − 1 + v 0‖<br />

c sinh (act) ]<br />

Ê,<br />

(C.21)<br />

where v 0‖ and v 0⊥ are the components of v 0 parallel and perpendicular to the direction<br />

of the field,<br />

v 0‖ = (v 0·Ê)Ê, v 0⊥ = v 0 − (v 0·Ê)Ê (C.22)<br />

and<br />

The velocity of the particle is<br />

a ≡ Z 0eE<br />

m e c 2 γ 0<br />

= Z 0eE<br />

E 0<br />

. (C.23)<br />

v(t) = v 0⊥ + [ c sinh (act) + v 0‖ cosh (act) ] Ê<br />

= v 0 + { c sinh (act) + v 0‖ [cosh (act) − 1] } Ê. (C.24)<br />

Since the scalar potential for the constant field is ϕ(r) = −E ·r, the kinetic energy of<br />

the particle varies with time and is given by<br />

E(t) = E 0 − Z 0 eE·[r 0 − r(t)] .<br />

(C.25)<br />

1 0<br />

a b c<br />

5<br />

z (cm)<br />

0<br />

E<br />

- 5<br />

θ<br />

v 0<br />

f g h<br />

- 1 0<br />

0 1 0 2 0 3 0<br />

x<br />

(cm)<br />

Figure C.1: Trajectories of electrons and positrons in a uniform electric field of 511 kV/cm.<br />

Continuous curves represent exact trajectories obtained from eq. (C.21). The dashed lines are<br />

obtained by using the first-order numerical tracking method described by eqs. (C.14)-(C.20)<br />

with δ E = δ E = δ v = 0.02. The displayed trajectories correspond to the following cases. a:<br />

positrons, E 0 = 0.1 MeV, θ = 135 deg. b: positrons, E 0 = 1 MeV, θ = 135 deg. c: positrons,<br />

E 0 = 10 MeV, θ = 135 deg. f: electrons, E 0 = 0.2 MeV, θ = 90 deg. g: electrons, E 0 = 2<br />

MeV, θ = 90 deg. h: electrons, E 0 = 20 MeV, θ = 90 deg.

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