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PENELOPE 2003 - OECD Nuclear Energy Agency

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228 Appendix C. Electron/positron transport in electromagnetic fields<br />

Fig. C.1 displays trajectories of electrons and positrons with various initial energies<br />

and directions of motion in a uniform electric field of 511 kV/cm directed along the<br />

positive z-axis. Particles start from the origin (r 0 = 0), with initial velocity in the<br />

xz-plane forming an angle θ with the field, i.e. v 0 = (sin θ, 0, cos θ), so that the whole<br />

trajectories lie in the xz-plane. Continuous curves represent exact trajectories obtained<br />

from the analytical formula (C.21). The dashed curves are the results from the firstorder<br />

tracking algorithm described above [eqs. (C.14)-(C.20)] with δ E = δ E = δ v = 0.02.<br />

We show three positron trajectories with initial energies of 0.1, 1 and 10 MeV, initially<br />

moving in the direction θ = 135 deg. Three trajectories of electrons that initially move<br />

perpendicularly to the field (θ = 90 deg) with energies of 0.2, 2 and 20 MeV are also<br />

depicted. We see that the tracking algorithm gives quite accurate results. The error can<br />

be further reduced, if required, by using shorter steps, i.e. smaller δ-values.<br />

C.1.2<br />

Uniform magnetic fields<br />

We now consider the motion of an electron/positron, with initial position r 0 and velocity<br />

v 0 , in a uniform magnetic field B. Since the magnetic force is perpendicular to the<br />

velocity, the field does not alter the energy of the particle and the speed v(t) = v 0 is a<br />

constant of the motion. It is convenient to introduce the precession frequency vector ω,<br />

defined by (notice the sign)<br />

ω ≡ − Z 0eB<br />

m e γc = −Z 0ecB<br />

E 0<br />

, (C.26)<br />

and split the velocity v into its components parallel and perpendicular to ω,<br />

Then, the equation of motion (C.7) becomes<br />

v ‖ = (v· ˆω) ˆω, v ⊥ = v − (v· ˆω) ˆω. (C.27)<br />

dv ‖<br />

dt = 0,<br />

dv ⊥<br />

dt<br />

= ω×v ⊥ . (C.28)<br />

The first of these eqs. says that the particle moves with constant velocity v 0‖ along<br />

the direction of the magnetic field. From the second eq. we see that, in the plane<br />

perpendicular to B, the particle describes a circle with angular frequency ω and speed<br />

v 0⊥ (which is a constant of the motion). The radius of the circle is R = v 0⊥ /ω. That<br />

is, the trajectory is an helix with central axis along the B direction, radius R and pitch<br />

angle α = arctan(v 0‖ /v 0⊥ ). The helix is right-handed for electrons and left-handed for<br />

positrons (see fig. C.2).<br />

In terms of the path length s = tv 0 , the equation of motion takes the form<br />

r(s) = r 0 + s v 0<br />

v 0‖ + R [1 − cos(s ⊥ /R)] ( ˆω׈v 0⊥ ) + R sin(s ⊥ /R)ˆv 0⊥ ,<br />

(C.29)

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