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Conformally Invariant Variational Problems. - SAM

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Combining (II.18) and (II.19) implies that<br />

∀x ∈ U (A | x−x 0 | 2 +B)(C | u(x)−y 0 | 2 +D) ≡ 1<br />

(II.20)<br />

As a consequence of (II.20) we obtain in particular that the<br />

image of a sphere of radius R centered at x 0 and included in U<br />

is contained in a sphere of center y 0 and radius ρ such that<br />

cρ 2 +D =<br />

1<br />

AR 2 +B<br />

(Applying the same argument to u −1 gives that<br />

u(∂B R (x 0 )) = ∂B ρ (y 0 ))<br />

Let V 0 be a unit vector of R n and consider the line passing by<br />

n 0 and oriented along V 0 . Its parametric equation is given by<br />

x(t) = tV 0 +x 0 . Since U is conformal and since it is sending the<br />

sphere centered at x 0 onto the spheres centered at<br />

y 0 , y(t) = U(x(t))is then a path that remainsorthogonalto this<br />

foliation of spheres and it has to be then contained is a straight<br />

line passing by y 0 .<br />

∀s,< τ s.t. y(t) ∈ u(U) for t ∈ [s,τ] we have<br />

| y(τ)−y(s) |=<br />

∫ τ<br />

s<br />

| ẏ | (+)dt =<br />

=<br />

=<br />

∫ τ<br />

∫s<br />

τ<br />

∫s<br />

τ<br />

Combining (II.20) and (II.21) we have<br />

s<br />

e λ | ẋ | dt<br />

1<br />

A | x−x 0 | 2 +B | ẋ | dt<br />

dt<br />

(II.21)<br />

At 2 +B<br />

(∫ τ<br />

C<br />

s<br />

) 2<br />

dt<br />

+D =<br />

At 2 +B<br />

1<br />

A | τ −s | 2 +B<br />

(II.22)<br />

12

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