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Conformally Invariant Variational Problems. - SAM

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There exists a constant C > 0, such that, if one assumes that<br />

∫<br />

|∇⃗n| 2 < 8π , (X.146)<br />

D 3<br />

2<br />

then there exists ⃗e 1 and ⃗e 2 in W 1,2 (D 2 ,S m−1 ) such that<br />

⃗n = ⋆(⃗e 1 ∧⃗e 2 ) ,<br />

(X.147)<br />

and 60<br />

∫<br />

D 2<br />

2∑<br />

|∇⃗e i | 2 dx 1 dx 2 ≤ C<br />

i=1<br />

∫<br />

D 2 |∇⃗n| 2 dx 1 ,dx 2 .<br />

(X.148)<br />

✷<br />

The requirement for the L 2 nom of ∇⃗n to be below a threshold,<br />

inequality (X.146), is necessary and it is conjectured in [He]<br />

that 8π/3 could be replaced by 8π and that this should be optimal.<br />

We can illustrate the need to have an energy restriction such<br />

as (X.146) with the following example :<br />

Let π be the stereographic projection from S 2 into C∪{∞}<br />

which sends the north pole N = (0,0,1) to 0 and the south pole<br />

S = (0,0,−1) to ∞. For λ sufficiently small we consider on D 2<br />

the following map ⃗n λ taking value into S 2 :<br />

⎧<br />

⃗n ⎪⎨ λ (x) := π −1 (λx) for |x| ≤ 1/2<br />

⎪⎩<br />

⃗n λ (x) := (1−r) π−1 (λx)+(r−1/2) S<br />

|(1−r) π −1 (λx)+(r−1/2) S|<br />

for 1 2<br />

< |x| ≤ 1.<br />

The map ⃗n λ has been constructed in such a way that on B 1/2 (0)<br />

itcoversthemostpartofS 2 conformally 61 andthemissingsmall<br />

60 The condition (X.147) together with the fact that the ⃗e i are in S m−1 valued imply,<br />

since ⃗n has norm one, that ⃗e 1 and ⃗e 2 are orthogonal to each other.<br />

61 The map x → π −1 (λx) is conformal.<br />

165

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