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Conformally Invariant Variational Problems. - SAM

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ii)<br />

iii)<br />

iv)<br />

limsupArea( Φ ⃗ k (D 2 )) < +∞<br />

k→+∞<br />

∀ρ < 1 limsup‖log|∇Φ ⃗ k |‖ L∞ (Bρ 2<br />

k→+∞<br />

(0)) < +∞ ,<br />

div<br />

[<br />

∇H ⃗ k −3π ⃗nk (∇H ⃗ k )+⋆(∇ ⊥ ⃗n k ∧H ⃗ ]<br />

k ) = 0 .<br />

Moreover we can assume that the immersion does not shift to<br />

infinity by taking<br />

⃗Φ k (0) = 0 . (X.178)<br />

Since the immersions Φ ⃗ k are conformal we have that<br />

∆Φ ⃗ k = 2e 2λ k Hk ⃗<br />

where e λ k = |∂ ⃗<br />

x 1Φk | = |∂ x2Φk ⃗ |.<br />

The conditions i) and iii) imply then the following<br />

∀ρ < 1 limsup‖∆Φ ⃗ k ‖ L2 (Bρ(0)) < +∞ .<br />

2<br />

k→+∞<br />

Moreover condition ii) implies<br />

∫<br />

limsup |∇Φ ⃗ k | 2 = limsup<br />

k→+∞ D 2 k→+∞<br />

2<br />

∫<br />

D 2 e 2λ k<br />

= limsup2Area( Φ ⃗ k (D 2 )) < +∞ .<br />

k→+∞<br />

Combining (X.178), (X.179) and (X.180) we obtain<br />

∀ρ < 1 limsup‖ Φ ⃗ k ‖ W<br />

2,2<br />

(Bρ 2<br />

k→+∞<br />

(0)) < +∞<br />

(X.179)<br />

(X.180)<br />

(X.181)<br />

We can then extract a subsequence that we keep denoting ⃗ Φ k<br />

such that there exists a map ⃗ Φ ∞ ∈ W 2,2<br />

loc (D2 ,R m ) for which<br />

⃗Φ k ⇀ ⃗ Φ ∞ weakly in W 2,2<br />

loc (D2 ,R m ) .<br />

181

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