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Conformally Invariant Variational Problems. - SAM

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vectors are denoted ⃗e i (t,p). The fact that this transport is parallel<br />

w.r.t. ∇ implies that (⃗e 1 (t,p),⃗e 2 (t,p)) realizes a positive<br />

orthonormal basis 48 of ⃗ Φ ∗ (t×T p Σ 2 ).<br />

Next we extend ⃗e i (t,p) parallely and locally in {t}×Σ 2 with<br />

respect again to ∇ along geodesics in {t} × Σ 2 starting from<br />

(t,p) for the induced metric ⃗ Φ ∗ t g R m.<br />

We will denote also e i := ( ⃗ Φ −1<br />

t ) ∗ ⃗e i . By definition one has<br />

⃗H(t,p) := 1 2<br />

2∑<br />

π ⃗n (d⃗e s ·e s ) = 1 2<br />

s=1<br />

2∑<br />

D es ⃗e s ,<br />

wherewehaveextendedtheuseofthenotationDforanysection<br />

of T ⊕N in an obvious way 49 . Hence we have<br />

D ∂<br />

⃗H = 1<br />

∂t 2<br />

2∑<br />

s=1<br />

s=1<br />

D ∂ (D es ⃗e s ) (X.69)<br />

∂t<br />

Since on ⃗ Φ([0,1] × {p}) one has ∇⃗e s ≡ 0 and since moreover<br />

∇+D coincides with the differentiation 50 d in R m one has<br />

D ∂(D es ⃗e s )(0,p) = D ∂ (d⃗e s ·e s )(0,p)<br />

∂t<br />

∂t<br />

= π ⃗n (d(∂ t ⃗e s )·e s )+π ⃗n (d⃗e s ·∂ t e s )<br />

(X.70)<br />

Observe that for a fixed q ∈ Σ 2 e s (t,q) stays in T q Σ 2 as t varies<br />

and then there isno need of a connectionto define ∂ t e s . Observe<br />

moreover that ∂ t e s = [∂ t ,e s ]. Thus (X.69) together with (X.70)<br />

48 Indeed<br />

(<br />

∇ ∂ ⃗e i = 0 ⇒ π T d⃗e i · ∂ )<br />

= 0<br />

∂t<br />

∂t<br />

〈 〉 ∂⃗ei<br />

⇒ ∀i,j<br />

∂t ,⃗e j = 0 ⇒ ∀i,j<br />

∂<br />

∂t = 0 .<br />

49 D X σ := π ⃗n (dσ ·X). D does not realizes a connection on the whole T ⊕N.<br />

50 d is the flat standard connection on TR m<br />

134

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