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Conformally Invariant Variational Problems. - SAM

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The definition of the Gauss curvature gives<br />

K ⃗n = − e−2λ<br />

2<br />

∇⃗n×∇ ⊥ ⃗n = − e−2λ<br />

2<br />

Inserting (X.95) in (X.94) gives<br />

−4e 2λ ⃗ H (H 2 −K)+∇H ·[∇⃗n+⃗n×∇ ⊥ ⃗n ]<br />

This becomes<br />

= Hdiv [ ∇⃗n−⃗n×∇ ⊥ ⃗n ] .<br />

−4e 2λ H ⃗ (H 2 −K)−2∆H ⃗n<br />

[<br />

= div −2∇H ⃗n+H ∇⃗n− H ⃗ ]<br />

×∇ ⊥ ⃗n<br />

div [ ⃗n×∇ ⊥ ⃗n ] (X.95)<br />

.<br />

(X.96)<br />

(X.97)<br />

Usingnow”intrinsicnotations”(independentoftheparametrization)<br />

on (Σ 2 ,g), (X.97) says<br />

4 H ⃗ (H 2 −K)+2∆ g H ⃗n<br />

[<br />

= d ∗ g<br />

−2dH ⃗n+Hd⃗n−∗ H ⃗ ]<br />

×d⃗n<br />

.<br />

(X.98)<br />

which is the desired identity (X.85) and theorem X.7 is proved<br />

in codimension 1.<br />

✷<br />

Before to proceed to the proof of theorem X.7 in arbitrary<br />

codimensionwe first introducesome complexnotationsthatwill<br />

be useful in the sequel. Assume Φ ⃗ is a conformal immersion<br />

into R m , one denotes z = x 1 + ix 2 , ∂ z = 2 −1 (∂ x1 − i∂ x2 ), ∂ z =<br />

2 −1 (∂ x1 +i∂ x2 ).<br />

Moreover we denote 55<br />

⎧<br />

⎨ ⃗e z := e −λ ∂ zΦ ⃗ = 2 −1 (⃗e 1 −i⃗e 2 )<br />

⎩<br />

⃗e z := e −λ ∂ zΦ ⃗ = 2 −1 (⃗e 1 +i⃗e 2 )<br />

55 Observe that the notation has been chosen in such a way that ⃗e z =⃗e z .<br />

148

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