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Conformally Invariant Variational Problems. - SAM

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This last identity written with the complex coordinate z is exactly<br />

(X.100) and lemma X.3 is proved. ✷<br />

Before to move to the proof of theorem X.7 we shall need two<br />

more lemma. First we have<br />

Lemma X.4. Let ⃗ Φ be a conformal immersion of the disc D 2<br />

into R m , denote z := x 1 +ix 2 , e λ := |∂ x1<br />

⃗ Φ| = |∂x2 ⃗ Φ| denote<br />

⃗e i := e −λ ∂ xi<br />

⃗ Φ ,<br />

(X.111)<br />

and let ⃗ H 0 be the Weingarten Operator of the immersion expressed<br />

in the conformal coordinates (x 1 ,x 2 ) :<br />

⃗H 0 := 1 2 [I(⃗e 1,⃗e 1 )−I(⃗e 1 ,⃗e 1 )−2iI(⃗e 1 ,⃗e 2 )]<br />

Then the following identities hold<br />

and<br />

∂ z<br />

[<br />

e λ ⃗e z<br />

]<br />

=<br />

e 2λ<br />

2 ⃗ H , (X.112)<br />

∂ z<br />

[<br />

e −λ ⃗e z<br />

]<br />

=<br />

1<br />

2 ⃗ H 0 . (X.113)<br />

✷<br />

Proof of lemma X.4. The first identity (X.112) comes simply<br />

from the fact that ∂ z ∂ zΦ ⃗ =<br />

1<br />

4 ∆⃗ Φ, from (X.117) and the expression<br />

of the mean curvature vector in conformal coordinates that<br />

we have seen several times and which is given by<br />

⃗H = e−2λ<br />

2 ∆⃗ Φ .<br />

It remains to prove the identity (X.113). One has moreover<br />

[ ]<br />

∂ z e λ ⃗e z = ∂z ∂ zΦ ⃗<br />

1<br />

[<br />

]<br />

= ∂ 2 x<br />

⃗Φ−∂ 2<br />

4<br />

2 1 x<br />

⃗Φ−2i ∂ 2 ⃗ 2<br />

2<br />

x 1 x 2Φ . (X.114)<br />

152

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