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Conformally Invariant Variational Problems. - SAM

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quantity<br />

div<br />

[<br />

2∇H ⃗ −3H∇⃗n−∇ ⊥ ⃗n× H ⃗ ]<br />

is an ”honest” distribution in D ′ (D 2 ) whereas, under such minimal<br />

assumption<br />

∆ g H +2H (H 2 −K)<br />

has no distributional meaning at all. This is why the conservative<br />

form of the Willmore surface equation is more suitable<br />

to solve the analysisquestions i)···vi) we are asking. The same<br />

happens in higher codimension as well. Using (X.88), one sees<br />

that, under the assumption that ∇⃗n ∈ L 2 one has<br />

∇ ⃗ H −3π ⃗n (∇ ⃗ H)+⋆(∇ ⊥ ⃗n∧ ⃗ H) ∈ H −1 +L 1<br />

which is again an honest distribution.<br />

The second equation in (X.89) is in conservative-elliptic<br />

form which is critical in 2 dimension under the assumption<br />

that⃗n ∈ W 1,2 . For a sake of claritywe present it in codimension<br />

1 though this holds identically in arbitrary codimension.<br />

In codimension 1 we write the Willmore surface equation as<br />

follows<br />

∆H ⃗ 3<br />

= div[<br />

2 H ∇⃗n+ 1 ]<br />

2 ∇⊥ ⃗n× H ⃗ (X.90)<br />

the right-hand-side of (X.90) is the flat Laplacian of H ⃗ and the<br />

left-hand-side is the divergence of a R m vector-field wich is a<br />

bilinear map of the second fundamental form. Assuming hence<br />

⃗n ∈ W 1,2 wededuce 3/2H∇⃗n+1/2∇ ⊥ ⃗n× H ⃗ ∈ L 1 (D 2 ). Adams<br />

result on Riesz potentials [Ad] implies that<br />

[ 3<br />

∆ −1<br />

0 div 2 H∇⃗n+ 1 ]<br />

2 ∇⊥ ⃗n× H ⃗ ∈ L 2,∞<br />

where ∆ −1<br />

0 is the Poisson Kernel on the disc D 2 . Inserting this<br />

information back in (X.90) we obtain H ⃗ ∈ L 2,∞<br />

loc (D2 ) which is<br />

145

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