Conformally Invariant Variational Problems. - SAM
Conformally Invariant Variational Problems. - SAM
Conformally Invariant Variational Problems. - SAM
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quantity<br />
div<br />
[<br />
2∇H ⃗ −3H∇⃗n−∇ ⊥ ⃗n× H ⃗ ]<br />
is an ”honest” distribution in D ′ (D 2 ) whereas, under such minimal<br />
assumption<br />
∆ g H +2H (H 2 −K)<br />
has no distributional meaning at all. This is why the conservative<br />
form of the Willmore surface equation is more suitable<br />
to solve the analysisquestions i)···vi) we are asking. The same<br />
happens in higher codimension as well. Using (X.88), one sees<br />
that, under the assumption that ∇⃗n ∈ L 2 one has<br />
∇ ⃗ H −3π ⃗n (∇ ⃗ H)+⋆(∇ ⊥ ⃗n∧ ⃗ H) ∈ H −1 +L 1<br />
which is again an honest distribution.<br />
The second equation in (X.89) is in conservative-elliptic<br />
form which is critical in 2 dimension under the assumption<br />
that⃗n ∈ W 1,2 . For a sake of claritywe present it in codimension<br />
1 though this holds identically in arbitrary codimension.<br />
In codimension 1 we write the Willmore surface equation as<br />
follows<br />
∆H ⃗ 3<br />
= div[<br />
2 H ∇⃗n+ 1 ]<br />
2 ∇⊥ ⃗n× H ⃗ (X.90)<br />
the right-hand-side of (X.90) is the flat Laplacian of H ⃗ and the<br />
left-hand-side is the divergence of a R m vector-field wich is a<br />
bilinear map of the second fundamental form. Assuming hence<br />
⃗n ∈ W 1,2 wededuce 3/2H∇⃗n+1/2∇ ⊥ ⃗n× H ⃗ ∈ L 1 (D 2 ). Adams<br />
result on Riesz potentials [Ad] implies that<br />
[ 3<br />
∆ −1<br />
0 div 2 H∇⃗n+ 1 ]<br />
2 ∇⊥ ⃗n× H ⃗ ∈ L 2,∞<br />
where ∆ −1<br />
0 is the Poisson Kernel on the disc D 2 . Inserting this<br />
information back in (X.90) we obtain H ⃗ ∈ L 2,∞<br />
loc (D2 ) which is<br />
145