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Conformally Invariant Variational Problems. - SAM

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maps, namely<br />

∑n+1<br />

(<br />

−∆u i = ν(u) i ∇(ν(u)) j −ν(u) j ∇(ν(u)) i)·∇u j .<br />

j=1<br />

(VIII.4)<br />

On the contrary, the second step of the process can not a priori<br />

be extended. Indeed, one cannot justify that the vector field<br />

ν(u) i ∇(ν(u)) j −ν(u) j ∇(ν(u)) i<br />

is divergence-free. This was true so long as N n was the sphere<br />

S n , butitfailssosoonasthemetriciseversoslightlyperturbed.<br />

What remainshoweverrobustisthe antisymmetryofthe matrix<br />

Ω := ( ν(u) i ∇(ν(u)) j −ν(u) j ∇(ν(u)) i) i,j=1···n+1<br />

. (VIII.5)<br />

It turns out that the antisymmetry of Ω lies in the heart of<br />

the problem we have been tackling in these lecture notes. The<br />

following result sheds some light onto this claim.<br />

Theorem VIII.1. [Riv1] Let Ω be a vector field in L 2 (∧ 1 D 2 ⊗<br />

so(m)), thus takings values in the space antisymmetric m × m<br />

matrices so(m). Suppose that u is a map in W 1,2 (D 2 ,R m ) satisfying<br />

the equation 21<br />

−∆u = Ω·∇u in D ′ (D 2 ) . (VIII.6)<br />

Then there exists some p > 2 such that u ∈ W 1,p<br />

loc (D2 ,R m ). In<br />

particular, u is Hölder continuous.<br />

✷<br />

Prior to delving into the proof of this theorem, let us first examine<br />

some of its implications towards answering the questions<br />

we aim to solve.<br />

21 In local coordinates, (VIII.6) reads<br />

−∆u i =<br />

m∑<br />

Ω i j ·∇u j ∀ i = 1···m .<br />

j=1<br />

77

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