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Introduction to Maya Hieroglyphs - Wayeb

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Kettunen & Helmke 2011<br />

Appendices<br />

3. Add the GMT-correlation constant (584 285) <strong>to</strong> the <strong>Maya</strong> day number <strong>to</strong> give its corresponding Julian<br />

Day Number (JDN):<br />

MDN: GMT: JDN:<br />

1 406 446 584 285 1 990 731<br />

4. From this JDN, the nearest smaller JDN (in the table below) is then subtracted:<br />

year: JDN: year: JDN:<br />

1 1 721 060 1100 2 122 827<br />

100 1 757 585 1200 2 159 351<br />

200 1 794 109 1300 2 195 876<br />

300 1 830 633 1400 2 232 400<br />

400 1 867 157 1500 2 268 924<br />

500 1 903 682 1600 2 305 448<br />

600 1 940 206 1700 2 341 973<br />

700 1 976 730 1800 2 378 497<br />

800 2 013 254 1900 2 415 021<br />

900 2 049 779 2000 2 451 545<br />

1000 2 086 303 ∗<br />

Julian Day Numbers (JDN) for January 1st in the Gregorian calendar (years AD 1⎯2000).<br />

JDN #1 JDN #2 remainder:<br />

1 990 731 1 976 730 14 001<br />

5. Calculate the number of (365 day) years and days in the remainder number:<br />

remainder: days in a (vague) year: result:<br />

14 001 365<br />

38 years<br />

131 days<br />

6. Take in<strong>to</strong> account the leap days (one every fourth year) and leap centuries (those that are divisible by<br />

400 (i.e. AD 400, 800, 1200, 1600, 2000, etc.) and subtract the number of leap days between AD 700<br />

(closest smaller JDN) and 738 (700 + the division result above):<br />

Closest smaller JDN: division result: leap days <strong>to</strong> be subtracted: final result:<br />

700<br />

38 years<br />

131 days<br />

-9 days<br />

738 years<br />

122 days<br />

Here the division is 38 years divided by 4 – for which we obtain 9,5. Counting only whole days we thus<br />

obtain 9 days <strong>to</strong> subtract. <strong>Maya</strong> Long Count date 9.15.6.14.6 corresponds, therefore, <strong>to</strong> the 122 th day of the<br />

year AD 738; i.e. May 2 nd AD 738.<br />

53/154

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